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How many atoms are in 10g of nitrogen?
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
How many moles of nitrogen are contained in 1.61 x 10 atoms of nitrogen?
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
What is the mass of nitrogen in grams?
One mole of atoms of an element is equal to the atomic mass of that element expressed in grams. Nitrogen-14 so one mole of nitrogen weighs 14 g
What is the molar mass of nitrogen dioxide to the nearest gram?
The molar mass of nitrogen dioxide is 46.0055 g.
How does the number of atoms in one mole of beryllium compare with the number of atoms in one mole of magnesium?
One mole of any element contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms. Beryllium and magnesium are both in Group 2 of the periodic table, so they have the same number of atoms in one mole.
How many particles are in one mole of nitrogen dioxide?
6.02x1023 particles are in one mole of nitrogen dioxide. One mole of anything, be it nitrogen dioxide of hydrogen monoxide (water), will always equal to 6.02x1023 (a very large number!) of particles. 6.02x1023 particles are in one mole of nitrogen dioxide. One mole of anything, be it nitrogen dioxide of hydrogen monoxide (water), will always equal to 6.02x1023 (a very large number!) of particles.
What is the empirical formula of a compound that contains 0.20 moles of nitrogen atoms and 0.40 moles of oxygen atoms?
Divide the larger by the smaller mole number. The smaller mole number is assumed to be 1. 0.40/0.20 = 2 As nitrogen is 0.20 moles we have 1 atom of it and 2 atoms of oxygen, so NO2 is the empirical formula (nitrogen dioxide).
How many atoms of nitrogen are in 10g of NH4NO3?
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
How many moles of oxygen atoms are present in one half mole of carbon dioxide molecules?
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
How many nitrogen atoms are in .25 mole of nitrogen gas?
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
How many atoms are in 1.38 mole of nitrogen?
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
Why might the expression 1 mole of nitrogen be confusing?
The confusion might arise because the term "mole" is a unit of measurement for the amount of substance, while "nitrogen" refers to a specific element. So saying "1 mole of nitrogen" could be ambiguous without specifying whether it refers to 1 mole of nitrogen atoms or 1 mole of nitrogen molecules (N2).
What is the mass of the nitrogen atoms in one mole of cadmium nitrate?
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
How many atoms are in 10g of nitrogen?
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
What is the number of atoms in 3.4 moles of nitrogen?
At standard temperature and pressure, nitrogen exists as diatomic molecules. Therefore the number of atoms in 3.4 moles is 2 X 3.4 X Avogadro's Number, or 4.1 X 1024 atoms, to the justified number of significant digits.
How many nitrogen atoms are in 25 g of CONH22 or Urea?
There are approximately 3.01 moles of urea in 25 g of CONH2, so there are 3.01 moles of nitrogen atoms. Therefore, there are 3.01 moles * 2 nitrogen atoms/molecule = 6.02 moles of nitrogen atoms in 25 g of CONH2, or urea.
How many nitrogen atoms are in 18.8 g of barium nitride?
Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.
