If your are talking about s shell search then # of subshells equals n-1. So if n=3 the number of subshells is two.
If your are talking about periodic chemistry the number of subshells for n=3 is six.
If your are talking about the Weriner progression then ss= n!/(n-3)!
Atomic number equals the number of protons, the (atomic) mass number equals the sum of (the number of) protons and neutrons of the same element.The answer is: they're differing in the number of neutrons(Mathematically: Where A = p and M = p + n, the difference in A and M is n)
In an atom, the number of electrons with quantum number n equals 2 is determined by the formula 2n^2. For n = 2, the maximum number of electrons is 2(2)^2 = 8.
The expression (4P1) represents the number of permutations of 4 items taken 1 at a time. It is calculated using the formula (nPr = \frac{n!}{(n-r)!}), where (n) is the total number of items and (r) is the number of items to choose. For (4P1), this equals (\frac{4!}{(4-1)!} = \frac{4!}{3!} = 4). Therefore, (4P1 = 4).
There are a total of three p orbitals for an atom with principal quantum number n = 2: px, py, and pz. These orbitals are oriented along the x, y, and z axes.
As n increases, the energy increases. Therefore, electron in the shell of n=100 will have highest energy. But the fact is that there isn't any shell with n=100. Also, n can have values starting from 1 and thus n=0 is not possible as well.
They are letters. s, p, and d 2s2 2p6 3s2 3p6 3d10 A full n = 3 level.
The number of subshells present in a principal energy shell is equivalent to the principal quantum number. For example, in the first principal energy shell (n=1), there is only one subshell (s). In the second principal energy shell (n=2), there are two subshells (s and p), and so on.
3 Number of Valves on a Trumpet
3 (n + 7) = 16
one
Given m equals 3 and n equals 1 then m3n3 equals?m3n3 = m*3*n*3 = 3*3*1*3 = [ 27 ]
125
n = 3
n/2 + 6 = n/3 so 6 = n/3 - n/2 = 2n/6 - 3n/6 = -n/6 and so n = -36
n1 has 1 n2 has 4
Yes. It represents the third energy level.
3 6