On the surface of Jupiter the acceleration due to gravity is about 3 times that of earth would would be the mass of a 170kg rock on Jupiter?

Answer 1

Assuming it is really 3 times as much (I did not look it up), on Earth, the gravitation is approximately 10 Newton / kilogram; on Jupiter it would be 30 Newton / Kilogram. Multiply this by 0.4 kg., and you get a weight of 12 Newton.

Answer 2

Assuming it is really 3 times as much (I did not look it up), on Earth, the gravitation is approximately 10 Newton / kilogram; on Jupiter it would be 30 Newton / Kilogram. Multiply this by 0.4 kg., and you get a weight of 12 Newton.

Assuming it is really 3 times as much (I did not look it up), on Earth, the gravitation is approximately 10 Newton / kilogram; on Jupiter it would be 30 Newton / Kilogram. Multiply this by 0.4 kg., and you get a weight of 12 Newton.

Assuming it is really 3 times as much (I did not look it up), on Earth, the gravitation is approximately 10 Newton / kilogram; on Jupiter it would be 30 Newton / Kilogram. Multiply this by 0.4 kg., and you get a weight of 12 Newton.

Assuming it is really 3 times as much (I did not look it up), on Earth, the gravitation is approximately 10 Newton / kilogram; on Jupiter it would be 30 Newton / Kilogram. Multiply this by 0.4 kg., and you get a weight of 12 Newton.

Answer 3

To find the mass of the 170kg rock on Jupiter, we can use the formula ( F = mg ) where ( F ) is the weight of the rock, ( m ) is the mass of the rock, and ( g ) is the acceleration due to gravity.

If the acceleration due to gravity on Jupiter is 3 times that of Earth, then the acceleration due to gravity on Jupiter is ( 3 \times 9.81 = 29.43 , m/s^2 ).

So, the weight of the rock on Jupiter would be ( F = 170 \times 29.43 = 5003.1 , N ).

To find the mass of the rock, we rewrite the formula: ( m = \frac{F}{g} ) where ( F ) is the weight of the rock and ( g ) is the acceleration due to gravity on Jupiter.

Therefore, the mass of the 170kg rock on Jupiter would be ( m = \frac{5003.1}{29.43} \approx 170 , kg ).

Answer 4

A 3 kg block is pulled across a table by a string with force of 40 N the block experiences a friction force of 5N what is the acceleration of block

Answer 5

510