6.023 x 1023
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
Thast is one mole. 26.98 grams/per mole is the mass.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------
In one mole of aluminum chloride (AlCl₃), there are three moles of chlorine atoms. This is because each formula unit of AlCl₃ contains three chlorine (Cl) atoms. Therefore, in one mole of AlCl₃, there are 3 moles × 6.022 × 10²³ (Avogadro's number) = 1.8066 × 10²⁴ chlorine atoms.
In one mole of aluminum III oxide (Al2O3), there are 2 moles of aluminum atoms (since there are 2 aluminum atoms in each formula unit of Al2O3) and 3 moles of oxygen atoms. Therefore, one mole of aluminum III oxide contains 2 + 3 = 5 moles of atoms. Avogadro's number (6.022 x 10^23) of atoms can be found in one mole of any substance.
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
It isn't. The mass of one mole of aluminum is less than the mass of one mole of copper. The number of atoms in one mole of aluminum is the same as the number of atoms in one mole of copper, which is 6.022 x 1023, also known as Avogodro's number.
In 1 mole of aluminum oxide (Al2O3), there are 6.022 x 10^23 particles, which is known as Avogadro's number. This includes 2 atoms of aluminum and 3 atoms of oxygen per formula unit of aluminum oxide.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
Thast is one mole. 26.98 grams/per mole is the mass.
The molar mass of aluminum is 26.98 g/mol. To find the number of atoms in 16.2 g of aluminum, first calculate moles (16.2 g / 26.98 g/mol), then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
Aluminum is number 13 on the periodic table so each aluminum atom has 13 protons and 13 electrons.One mole of anything has is 6.022x1023 atoms (Avogadro's number)So 1 mole of aluminum has 13x6.022x1023 electrons
There are Avogadro's Number of atoms present, which is one gram mole of aluminum. This is roughly 27 g.
1 mole of 02 gas has 12,044 281 714.1023 atoms.
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------