2* (4^2) or 32
Maximum of 32 electrons.
The maximum number of electrons with principal quantum number 4 and angular momentum quantum number 0 would be 2 electrons. This is because for each energy level (n), there can only be one orbital (l=0) present, and each orbital can hold a maximum of 2 electrons (with opposite spins, as per the Pauli exclusion principle).
An orbital can only occupy maximum of 2 electrons. As p orbital consist of 3 orbitals. And has 3 orientations. Px, Py, Pz. So as there are 3 orbitals so p orbital can occupy at the maximum 6 electrons regardless of principle quantum no.. In 4p 4 is principle quantum no. So it represent 4p represent the p orbital of 4th shell. So it also occupy at the maximum of 6 electrons.
The maximum number of s electrons that can exist in any one particular energy level is 2. This is because each s orbital can hold a maximum of 2 electrons due to the Pauli exclusion principle, which states that no two electrons in an atom can have the same set of quantum numbers.
Actually it is quite simple. If you are familier with the basics of the quantum theory you can see that the number of orbitals for any given principle quantum number is n^2. Since one orbital can carry a maximum of 2 electrons, the total number of electrons for a principle quantum number is 2 x n^2 = 2n^2 If you are unfamilier with quantum theory. It can be simplified like so - we know that electrons are present in three dimensional energy levels (orbitals). Each of these energy levels have may many sub orbitals. for example for the 1st energy level the number of sub orbitals is n^2 (n square) that is 1 x 1 = 1. then the total number of electrons for this energy level is 2n^2 = 2 x 1^2 = 2.
Maximum of 32 electrons.
The maximum number of electrons with principal quantum number 4 and angular momentum quantum number 0 would be 2 electrons. This is because for each energy level (n), there can only be one orbital (l=0) present, and each orbital can hold a maximum of 2 electrons (with opposite spins, as per the Pauli exclusion principle).
6
An orbital can only occupy maximum of 2 electrons. As p orbital consist of 3 orbitals. And has 3 orientations. Px, Py, Pz. So as there are 3 orbitals so p orbital can occupy at the maximum 6 electrons regardless of principle quantum no.. In 4p 4 is principle quantum no. So it represent 4p represent the p orbital of 4th shell. So it also occupy at the maximum of 6 electrons.
18 electrons can occupy the third energy levelIt is like this3s- 2 electrons3p- 6 electrons3d- 10 electrons
The maximum number of electrons that a single orbital can hold is 2, according to the Pauli exclusion principle. This is because each electron in an orbital must have a unique set of quantum numbers.
Pauli's exclusion principle
The principal energy level is represented by the main energy level number (n). The valence electrons are the electrons found in the outermost energy level of an atom, which corresponds to the highest principal energy level (n).
The maximum number of s electrons that can exist in any one particular energy level is 2. This is because each s orbital can hold a maximum of 2 electrons due to the Pauli exclusion principle, which states that no two electrons in an atom can have the same set of quantum numbers.
In an atom, the maximum number of electrons that can have the quantum number n=7 is 2*(7)^2 = 98 electrons. This is based on the formula 2n^2, which represents the maximum number of electrons that can occupy a given energy level in an atom.
The maximum number of electrons in any s sublevel is 2, irrespective of what the principal quantum number, i.e., the number before the s in an electron configuration, may be.
When yttrium forms a cation, it loses the outermost electrons first. Yttrium has an electron configuration of [Kr] 4d1 5s2, so it loses the 5s electrons first followed by the 4d electrons. The principle quantum number of the lost electrons is n=5.