The molecular mass of vitamin C (ascorbic acid) is 176,1241 and the chemical formula is C6H8O6.
To find the molecular formula from the empirical formula, we need to know the molar mass of the empirical formula. In this case, the empirical formula's molar mass is 88. To find the molecular formula, we divide the given molecular mass (176) by the empirical formula's molar mass (88) to get 2. This means the molecular formula of Vitamin C is twice the empirical formula, so the molecular formula is C6H8O6.
u c... d formula 4 vitamin B2 is C(17)H(20)N(4)O(6)... so.. after calculating using d periodic table... d answer will b:198!!! answer is not really guaranteed.. but if ur desperate, then juz take it!! CHEMISTRY is jus so GREAT, don't u think so? im juz a 17 years old gal with ambition 2 b a genius................
C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and has molar mass of 132 amu.
The empirical formula C2H3 has a molecular mass of 27 (C: 12, H: 1). To determine the molecular formula with a molecular mass of 54, the molecular formula would simply be double the empirical formula, so the molecular formula would be C4H6.
To find the mass percent of vitamin C in the solution, first calculate the moles of iodine used in the titration: ( \text{Moles of Iodine} = 0.005 , \text{M} \times 0.02135 , \text{L} = 0.00010675 , \text{moles} ). Assuming a 1:1 stoichiometry between iodine and vitamin C, this corresponds to 0.00010675 moles of vitamin C. The molar mass of vitamin C (ascorbic acid) is approximately 176.12 g/mol, so the mass of vitamin C is ( 0.00010675 , \text{moles} \times 176.12 , \text{g/g} \approx 0.0188 , \text{g} ) or 18.8 mg. The mass percent of vitamin C in the 500 mg tablet is then ( (18.8 , \text{mg} / 500 , \text{mg}) \times 100 \approx 3.76% ).
To find the molecular formula from the empirical formula, we need to know the molar mass of the empirical formula. In this case, the empirical formula's molar mass is 88. To find the molecular formula, we divide the given molecular mass (176) by the empirical formula's molar mass (88) to get 2. This means the molecular formula of Vitamin C is twice the empirical formula, so the molecular formula is C6H8O6.
Yes. Vitamin C (ascorbic acid) is a molecular compound.
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I think it's C3H4O3.
The molecular formula for cobalamin (Vitamin B12) is C 63 H 88 CoN 14 O 14 P.
Vitamin C (ascorbic acid) does contain oxygen and hydrogen atoms, like water, but its molecular structure is different. Vitamin C is a water-soluble vitamin with a different chemical composition and function than water. The molecular structure of vitamin C contains carbon, oxygen, and hydrogen atoms but is not solely composed of oxygen and hydrogen.
c6h8o6 is the molecular formula of ascorbic acid better known as vitamin C
C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and has molar mass of 132 amu.
396.61 - 396.65 or more exactly 396.63 amu
u c... d formula 4 vitamin B2 is C(17)H(20)N(4)O(6)... so.. after calculating using d periodic table... d answer will b:198!!! answer is not really guaranteed.. but if ur desperate, then juz take it!! CHEMISTRY is jus so GREAT, don't u think so? im juz a 17 years old gal with ambition 2 b a genius................
The compound C9H8O4 is aspirin. This compound has a molar mass of 180.1574 g/mol. Aspirin is made up of the elements carbon, hydrogen, and oxygen.
Mass of C-12 atom =12 amu8.5 times of mass of C-12 atom = 12 x 8.5 = 102 amuSo molecular mass of XY = 102 amusource- www.examville.com