Two identical charged particles moving with same speed enter a region of uniform magnetic field If one of these enters normal to the field direction and the other enters along a direction at 30 with?

Answer 1

So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field.

In the first case @ = 90 deg. As sin90 = 1 the force is Bqv.

In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv.

Hence the force on the latter will be half of that on the earlier one.

Answer 2

The charged particle entering perpendicular to the magnetic field will experience a force perpendicular to its velocity according to the right-hand rule. The charged particle entering at a 30-degree angle with the magnetic field will experience a force and a component of velocity along the magnetic field direction, resulting in a helical path. Both particles will move in circular paths, but the one at an angle will have a more complex trajectory due to the combination of the circular motion and the component of velocity along the field direction.