According to the NEC (national electric code) a maximum of 2% voltage drop is allowed.
For a 200 amp service, a 250 MCM wire rated for 90°C can typically be run up to around 200-250 feet before exceeding voltage drop limits set by the National Electrical Code (NEC). However, it is recommended to consult with a licensed electrician to determine the exact length based on factors such as ambient temperature, conductor insulation, and specific installation conditions.
A #14 copper wire with an insulation factor of 90 degrees C is rated at 15 amps. To answer your question for voltage drop at 200 feet a voltage needs to be stated. Assuming the voltage of 120 is used to maintain 15 amps at the distance of 200 feet a #6 copper conductor will limit the voltage drop to less that 3 percent. Assuming the voltage of 240 is used to maintain 15 amps at the distance of 200 feet a #10 copper conductor will limit the voltage drop to less that 3 percent.
There are formulae, but it is much easier to simply use a "voltage drop calculator" (many interactive ones can be found online), plug in your values and increase your conductor size until the calculated voltage drop over the required distance, at 1.25 times the required load (80 percent design factor), does not exceed 5 percent (the allowed voltage drop in USA and Canadian electrical codes, other countries vary). For instance, your example could use 14 AWG, giving you a 4.8 percent drop, or 12 AWG for a 3 percent drop (assuming copper). If you were to use aluminum, you would need the larger conductor.
A 12 AWG wire would give you approximately 2.6 percent drop, which is less than the maximum allowable voltage drop. 14 AWG would drop you 10 volts (4.2 percent), which is still workable until you factor in the 80 percent design factor (i.e., you are only allowed to run a circuit at 80 percent of its design capacity). If you REALLY need 15 amps, you have to design for 18.75 amps (which works out to a 14 AWG voltage drop of over 5 percent, which is not allowed), so you would need to use the larger wire (12 AWG) for a 3.3 percent drop.
The question is one of voltage loss. The goal is to have enough ampacity in the selected conductors to run the maximum load with only 3 percent voltage drop, caused by the resistance inherent in the wires. Plug your numbers into a voltage drop calculator online and see what pops out. At 120 volts you would get 3.1 percent drop using 3/0 wire. At 240 volts you could drop down three sizes to #1 AWG for 3.1 percent at max load, or 1/0 size for 2.5 percent drop at max load. Assuming copper wire at normal conditions of temperature.
100 percent means full voltage or 0 dB.When 75 percent of the voltage is lost you still have 25 percent of the voltage.25 percent means damped to (-)12 dB.
Percent Regulation is the regulation expressed as a percentage is a figure of merit used to specify the performance of a voltage regulator.
yes.. voltage regulation can be negative
80
This statement is correct.
10
The minimum allowed conductor for 120 volts, 15 amps at 325 feet would be 6 AWG, giving you a 4.8 percent voltage drop (at 18.75 amps, which is the derating for 15 amps being 80 percent of the design load). Five percent is the max allowed in US and Canadian electrical codes (US measured at outlet, Canadian measured at point of use). If you're using 240 volts, the min AWG would be 8 AWG for 3.8 percent drop.
The line voltage in the usa is 120V if the 2000V is for a tube in a microwave oven it generally depends on a transformer and rectifier so the line voltage will go down about 2% to retain the output
Assuming that you mean a mains plug, then the voltage across the live and the neutral pins depends entirely on the the supply coming in to the socket. North America is rated at 110V while in Europe, the standard voltage is 230V. All supply comanies are allowed a tolerance of a few percent either higher or lower than the rated voltage. However, on a project I worked on in Eastern Europe some years ago, I monitored the voltage and although it was supposed to be 220V in that particular country, what I saw was between 156V and 250V. So, even if you know what the voltage, should be, you can never rally be sure!
the voltage regulation (as a percent) = |V(no-load) -V(rated)|/|V(rated)| * 100 so if V(rated) = 24 V voltage regulation =10% then V(no-load) = 26.4 V
67%
Line regulation is a measure of the ability of the power supply to maintain its output voltage given changes in the input line voltage. Line regulation is expressed as percent of change in the output voltage relative to the change in the input line voltage.