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What Mass Of Calcium Carbonate Is Needed For Complete Reaction With The HCl In 2HCl(aq) plus CaCO 3 (s) CaCl 2 (aq) plus H 2 O(l) plus CO 2 (g)?
To determine the mass of calcium carbonate (CaCO₃) needed to react completely with hydrochloric acid (HCl), you can use stoichiometry. The balanced equation shows that 2 moles of HCl react with 1 mole of CaCO₃. Thus, for every 2 moles of HCl, you need 1 mole of CaCO₃. If you know the amount of HCl in moles, you can calculate the required moles of CaCO₃ and then convert that to mass using its molar mass (100.09 g/mol).
What else can I help you with?
Why is hydrated sodium carbonate and excess hydrochloric acid boiled when reacting together?
Boiling this is done to remove ALL carbon dioxide (as gas) from the solution, before titrating the HCl-excess 'back' with titrant sodium hydroxide. Otherwise CO2 is disturbing the reaction at the end point of this backtitration at pH = 7 to 8 indicated by phenolphtaleine)Na2CO3.xH2Oaq + 2HClaq --> 2NaClaq + H2Oliq + CO2(gas) + H+aq,(excess)(Don't forget to cool down after boiling)OH- + H+(excess) ==> H2OOH- + CO2 |-o-| 'nill'(= no reaction of CO2 to form HCO3-, which is formed at pH = 7 to 8)
Could the following chemical equation naoh aq plus hcl aq nacl s plus h2o l the reactant of naoh?
2NaOHaq + 2HClaq --> 2NaClaq + H2Ol is the perfect balanced equatiion,except the solubility (aq) of NaCl, so it is notNaCls but NaClaq
