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How joule Thomson experiment lead to coefficient?
The Joule Thomson experiment involves measuring the change in temperature of a gas as it expands through a throttle valve. The Joule Thomson coefficient is defined as the temperature change per unit pressure drop. By quantifying the temperature change in relation to the pressure drop, scientists can determine the Joule Thomson coefficient for a specific gas under certain conditions.
Why hydrogen and helium does not satisfy joule Thomson effect?
As the gs flow from high pressure to low pressur using the porus plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume
When a real gas undergoes joule Thomson expansion how does the temperature react?
The temperature of a real gas can either increase, decrease, or remain constant during Joule-Thomson expansion, depending on the initial conditions such as pressure and temperature. This is due to the interplay between the Joule-Thomson coefficient and the specific heat of the gas.
Why joule Thomson effect is not applicable for hydrogen and hellium?
As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume
Do gases cool when they are compressed?
Yes, gases cool when they are compressed because the compression increases the gas's density and reduces its volume, leading to a decrease in internal energy and a corresponding drop in temperature. This phenomenon is known as the Joule-Thomson effect.
What are the applications of Thomson effects?
two application joule thomson 1. linde methode 2. liquiefied
How is the Joule-Thomson effect calculated in thermodynamics?
The Joule-Thomson effect is calculated in thermodynamics by using the Joule-Thomson coefficient, which is the rate of change of temperature with pressure at constant enthalpy. This coefficient is determined by taking the partial derivative of temperature with respect to pressure at constant enthalpy. The formula for the Joule-Thomson coefficient is given by (T/P)H, where is the Joule-Thomson coefficient, T is temperature, P is pressure, and H is enthalpy.
What term describes the cooling of a gas by expansion?
Joule-Thomson effect.
Joule Thomson effect is temperature dependent or not?
The Joule-Thomson effect is temperature dependent. It describes the change in temperature of a gas as it expands or is compressed without doing external work. If the gas undergoes adiabatic expansion (no heat exchange with surroundings), its temperature will change depending on its initial temperature, pressure, and the nature of the gas.
How joule Thomson experiment lead to coefficient?
The Joule Thomson experiment involves measuring the change in temperature of a gas as it expands through a throttle valve. The Joule Thomson coefficient is defined as the temperature change per unit pressure drop. By quantifying the temperature change in relation to the pressure drop, scientists can determine the Joule Thomson coefficient for a specific gas under certain conditions.
Significance of joule Thomson effect?
It is an experiment in which the Joule-Thomson coefficient is measured. Basically, you are expanding a gas under adiabatic conditions to ensure constant enthalpy and you will notice that there will be a temperature change (most likely cooling).
Why hydrogen and helium does not satisfy joule Thomson effect?
As the gs flow from high pressure to low pressur using the porus plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume
When a real gas undergoes joule Thomson expansion how does the temperature react?
The temperature of a real gas can either increase, decrease, or remain constant during Joule-Thomson expansion, depending on the initial conditions such as pressure and temperature. This is due to the interplay between the Joule-Thomson coefficient and the specific heat of the gas.
What is the value of joule Thomson coefficient for Natural gas?
The Joule-Thomson coefficient for natural gas can vary depending on the specific composition of the gas. Generally, it is around 0.25 K/bar at room temperature and pressure for most natural gas compositions. However, this value can change with different operating conditions and gas compositions.
What are the uses and applications of joule's experiment?
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Why do compressed air get cold when released from a container?
When compressed air is released from a container, it expands rapidly, causing a drop in temperature due to the gas molecules losing energy as they spread out. This phenomenon is known as the Joule-Thomson effect.
Why joule Thomson effect is not applicable for hydrogen and hellium?
As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume
