Ni2+(aq) + 2e- Ni(s) and Mg(s) Mg2+(aq) + 2e-
Mg(s) Epi-Boii
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
The anode
Raw Onions Nutritional value per 100 g (3.5 oz) Energy 166 kJ (40 kcal) Carbohydrates 9.34 g Sugars 4.24 g Dietary fiber 1.7 g Fat 0.1 g saturated 0.042 g monounsaturated 0.013 g polyunsaturated 0.017 g Protein 1.1 g Water 89.11 g Vitamin A equiv. 0 μg (0%) Thiamine (Vit. B1) 0.046 mg (4%) Riboflavin (Vit. B2) 0.027 mg (2%) Niacin (Vit. B3) 0.116 mg (1%) Vitamin B6 0.12 mg (9%) Folate (Vit. B9) 19 μg (5%) Vitamin B12 0 μg (0%) Vitamin C 7.4 mg (12%) Vitamin E 0.02 mg (0%) Vitamin K 0.4 μg (0%) Calcium 23 mg (2%) Iron 0.21 mg (2%) Magnesium 0.129 mg (0%) Phosphorus 29 mg (4%) Potassium 146 mg (3%) Sodium 4 mg (0%) Zinc 0.17 mg (2%
mg answer k magisa mo
Mg(s) Apex baby
Ni2+(aq) + 2e- Ni(s) and Mg(s) Mg2+(aq) + 2e-
Zn2+(aq) + 2e- = Zn(s) and Mg(s) = Mg2+(aq) + 2e-
Mg(s)
4.2V
Mg(s) | Mg2+(aq)Au+(aq) | Au(s)
Mg(s) | Mg2+(aq)Au+(aq) | Au(s)
Mg(s) | Mg2+(aq) Au+(aq) | Au(s)
4.2 V
The voltage of a galvanic cell can be calculated using the standard reduction potentials of the half-reactions involved. For a cell with copper (Cu) and magnesium (Mg), the standard reduction potential for Cu²⁺/Cu is +0.34 V, and for Mg²⁺/Mg, it is -2.37 V. The overall cell potential (E°cell) can be calculated as E°(cathode) - E°(anode), resulting in E°cell = 0.34 V - (-2.37 V) = 2.71 V. Therefore, the voltage of the galvanic cell with copper and magnesium is 2.71 V.
Mg(s) Epi-Boii
The standard cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) can be represented as: Mg(s) | Mg²⁺(aq) || Au³⁺(aq) | Au(s). In this notation, magnesium is the anode (oxidation occurs) and gold is the cathode (reduction occurs), with the vertical bars separating different phases and the double vertical bar indicating the salt bridge.