30.1 percent by mass = 30.1 g HCOOH + 69.9 g H2O
moles HCOOH = 30.1 g x 1 mol/46 g = 0.654 moles
moles H2O = 69.9 g x 1 mol/18 g = 3.88 moles
Total moles = 4.53
mole fraction HCOOH = 0.654/4.53 = 0.144
mole fraction H2O = 3.88/4.53 = 0.856
molality = moles solute/kg solvent = 0.654/0.0699 = 9.36 m
The molality is 5,54.
Percent concentration could mean many things...MOLARITY is defined as the moles of solute per unit volume of solution so 5 moles of NaCl in one liter of solution would be 5M (molar) NaCl solution.(Note: Solution is the solvent and solute combined, usually the solid is added and then the solution is filled to a certain line once the solid has dissolved.)MOLALITY is defined as the moles of solute per kilogram of solvent (NOT solution). So 5 moles of NaCl in one kilogram of water makes 5 mol/kg NaCl. (sometimes the symbol m is used for molality but is often confused with the unit of meters).For other types of "percent concentration" of solutions check:http://en.wikipedia.org/wiki/ConcentrationA cursory glance seemed to confirm the accuracy of the information.
The apparent degree of dissociation of NaCl can be calculated using the formula: i = 1 + (ΔTf)/(Kf * m), where i is the van't Hoff factor, ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. Given the information, assuming Kf for water is 1.86 °C kg/mol and the molality is 0.5 mol/kg, you can calculate the van't Hoff factor to determine the apparent degree of dissociation.
The concentration of a solution refers to the amount of solute present in a given amount of solvent or solution. It can be expressed in various units such as molarity, molality, mass percent, or volume percent, depending on the context. Concentration is important in determining the properties and behavior of a solution.
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
The molality is 5,54.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
The mole fraction of HCl in a 20% aqueous solution can be calculated by converting the percentage to a molarity concentration. Assuming the density of the solution is 1 g/mL, a 20% solution means 20g of HCl in 100g of solution. If the molar mass of HCl is 36.5 g/mol, we can calculate the molarity and then use it to find the mole fraction of HCl in the solution.
To determine the molality of a solution using the mass percent of the solute, you need to first convert the mass percent to grams of solute per 100 grams of solution. Then, calculate the moles of solute using its molar mass. Finally, divide the moles of solute by the mass of the solvent in kilograms to find the molality of the solution.
The relationship between molality and mass percent in a solution is that they both measure the concentration of a solute in a solvent, but they do so in different ways. Molality is the number of moles of solute per kilogram of solvent, while mass percent is the mass of the solute divided by the total mass of the solution, multiplied by 100. They are related through the formula: mass percent (molality x molar mass of solute) / (density of solvent).
Molarity: the concentration of a solution in moles of solute per liter of solution. Molality: the concentration of a solution in moles of solute per kilogram of solvent. Mass percent: the percentage of the total mass of a solution that is contributed by the solute. Volume percent: the percentage of the total volume of a solution that is contributed by the solute. Parts per million (ppm): the concentration of a solution in parts per million by weight.
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
Formalin is 40% solution of formaldehyde not an acid.
You would need to add 18.75g of solid NaOH to the 750g of aqueous solution to obtain a 2.5% NaOH solution by mass.
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g