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Assuming that is is a solution of glucose in water, the answer is 93%.

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What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?

400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.


Five quantitative ways to describe the composition of solutions?

Molarity: the concentration of a solution in moles of solute per liter of solution. Molality: the concentration of a solution in moles of solute per kilogram of solvent. Mass percent: the percentage of the total mass of a solution that is contributed by the solute. Volume percent: the percentage of the total volume of a solution that is contributed by the solute. Parts per million (ppm): the concentration of a solution in parts per million by weight.


What is the amount of dissolved substance in a solution called?

The amount of dissolved substance in a solution is called the concentration of the solution. This can be expressed in various units such as molarity, molality, or weight/volume percentage.


How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?

To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.


What is the weight of 10 percent acetic acid?

The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.

Related Questions

What is another way to express the concentration of a glucose solution that is 0.01 percent by weight?

Another way to express the concentration of a 0.01 percent by weight glucose solution is to say it is a 100 parts per million (ppm) solution. This means there are 100 grams of glucose in every 1 million grams of solution.


What is the another way to express the concentration of a glucose solution that is 0.01 percent by weight?

Another way to express the concentration of a glucose solution that is 0.01 percent by weight is as 100 parts per million (ppm). This means there are 100 grams of glucose in 1 million grams of solution.


What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?

400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.


Five quantitative ways to describe the composition of solutions?

Molarity: the concentration of a solution in moles of solute per liter of solution. Molality: the concentration of a solution in moles of solute per kilogram of solvent. Mass percent: the percentage of the total mass of a solution that is contributed by the solute. Volume percent: the percentage of the total volume of a solution that is contributed by the solute. Parts per million (ppm): the concentration of a solution in parts per million by weight.


Formula for molality?

Molality (m) is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms and is expressed in mol/kg. The formula for molality is: [ molality (m) = \frac{moles\ of\ solute}{mass\ of\ solvent\ in\ kg} ]


How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?

About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.


What is mean by weight by weight?

"weight by weight" is term, we use in chemistry. it is similar to terms like molarity, molality, normality etc. "weight by weight" defines the ratio of solute vs solvent in solution or mixture specially when we deals with solid in solid mixture or solution


What is the amount of dissolved substance in a solution called?

The amount of dissolved substance in a solution is called the concentration of the solution. This can be expressed in various units such as molarity, molality, or weight/volume percentage.


What is the molality of a substance?

Molality is the number of moles of a solute divided by the weight of the solvent in kilograms.


Compute the boiling point elevation of a salt water solution that contains 3.40 g of NaCl dissolved in 148 ml of water?

The boiling point elevation of a solution can be calculated using the formula: ΔTb = i * Kf * m, where i is the van't Hoff factor, Kf is the cryoscopic constant for water (0.52 °C kg/mol), and m is the molality of the solution. First, calculate the molality of the NaCl solution using the given mass of NaCl and the molecular weight of NaCl to find the molality. Then, use this molality value in the formula along with the van't Hoff factor for NaCl in water (i = 2) to determine the boiling point elevation.


What is the weight percent of a caffeine solution made by dissolving 8.35 g of caffeine C8H10N4O2 in 75 g of benzene C6H6?

The weight percent of a caffeine solution made by dissolving 8.35 g of caffeine in 75 g of benzene is calculated as: Weight percent = (mass of caffeine / total mass of solution) * 100 Weight percent = (8.35 g / (8.35 g + 75 g)) * 100 Weight percent ≈ 10.0%


How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?

To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.