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If it is pure benzene and CCl4 your answer is; % Benzene = (m Benzene)/(m Total)*100 = 14.2 / (14.2 + 28) * 100 = 33.65 % If the solution is benzene and CCl4 dissolved in water or another solvent, the answer depends entirely on how much solvent you have.
Molarity is a concentration unit of solutions, pure benzene is not a solution so this term is meaningless for a pure liquid. In other words: Molarity of a solution is a numerical way of saying exactly how much solute is dissolved in a solvent .Molarity is equal to the moles of solute divided by the liters of solution. Molarity of a solution can be calculated by using the following formula: M= moles of solute/liters of solution
In a solution of HCL and water, H20 has stronger polar bonds toward HCL causing it to disassociate into H+ and Cl- Ions. Benzene doesnt have those types of polar bonds so HCL doesnt dissolve as readily. (salt and water1 vs. oil and water2.)(the second water acting as benzene would.)
the boiling point of platnium is 2500c
Benzene
0.736 i think good luck
no
Benzene, being a covalent compound is not soluble in water. So a solution of benzene in water is absurd. However in answering your question I would say that, as benzene is not soluble in water it does not function as an electrolyte. Some more improvement would be that benzene itself is not an electrolyte.
your momma destroyed the plants
If it is pure benzene and CCl4 your answer is; % Benzene = (m Benzene)/(m Total)*100 = 14.2 / (14.2 + 28) * 100 = 33.65 % If the solution is benzene and CCl4 dissolved in water or another solvent, the answer depends entirely on how much solvent you have.
No benzene is extremely hydrophobic and sits like an oil on top of the water.
calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetra chlorid
toluene is benzene with CH3 reacting this with KMnO4 in acidic solution will produce a benzene with a carboxylic acid (CH3 will be oxidized)
∆T = imK∆T = change in temp; i = van't Hoff factor (1 for non electrolyte); m = molality; K = constantm = 0.551 moles/0.899 kg = 0.612Look up the Kf and Kb for benzene and substitute in above equation and solve for ∆T.Add this to the normal b.p. and subtract it from the normal f.p. to get new b.p. and f.p.
This is because of the polarity of the solvents. Aqueous solution (H2O) is very polar and will produce H+ ions when HCL is added, thus resulting in a acidic solution. On the other hand, benzene, a nonpolar solvent will not produce H+ ions and no acidic properties.
New Temperature= 5.5 C - .431 C = 5.069 C Theres the answer, now figure out how to do it... -Greg
Nothing, they don't react with each other.