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If it is pure benzene and CCl4 your answer is;

% Benzene = (m Benzene)/(m Total)*100 = 14.2 / (14.2 + 28) * 100 = 33.65 %

If the solution is benzene and CCl4 dissolved in water or another solvent, the answer depends entirely on how much solvent you have.

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Q: What is the percent by mass of benzene in a solution containing 14.2 g of bezene in 28.0 g of carbon tetrachloride?
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