no
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.
Yes, gasoline is soluble in benzene. Both gasoline and benzene are hydrocarbons, so they can mix together to form a solution. Benzene is often used as a solvent for gasoline to help improve its combustion properties.
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
The pH of a solution of Na2SO4 at a concentration of 0.25M is about 7, which is neutral. Na2SO4 is a salt formed from a strong base (NaOH) and a strong acid (H2SO4), so it does not significantly affect the pH of the solution.
Aqueous KOH solution is a strong base that can deprotonate benzene to form the phenoxide ion. The reaction involves the substitution of an H atom on the benzene ring with a hydroxide ion from KOH, resulting in the formation of a phenol derivative.
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.
No benzene is extremely hydrophobic and sits like an oil on top of the water.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
Yes, gasoline is soluble in benzene. Both gasoline and benzene are hydrocarbons, so they can mix together to form a solution. Benzene is often used as a solvent for gasoline to help improve its combustion properties.
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
Chloroform is miscible with ethanol, carbon tetrachloride, benzene, diethyil ether etc.
The pH of a solution of Na2SO4 at a concentration of 0.25M is about 7, which is neutral. Na2SO4 is a salt formed from a strong base (NaOH) and a strong acid (H2SO4), so it does not significantly affect the pH of the solution.
Aqueous KOH solution is a strong base that can deprotonate benzene to form the phenoxide ion. The reaction involves the substitution of an H atom on the benzene ring with a hydroxide ion from KOH, resulting in the formation of a phenol derivative.
Benzene, being a covalent compound is not soluble in water. So a solution of benzene in water is absurd. However in answering your question I would say that, as benzene is not soluble in water it does not function as an electrolyte. Some more improvement would be that benzene itself is not an electrolyte.
The molar mass of benzene (C6H6) is 78.12 g/mol. To calculate the mass percent of benzene in a solution, divide the mass of benzene by the total mass of the solution, then multiply by 100. For example, if you have 10 g of benzene in a 100 g solution, the mass percent would be (10 g / 100 g) * 100 = 10%.
If it is pure benzene and CCl4 your answer is; % Benzene = (m Benzene)/(m Total)*100 = 14.2 / (14.2 + 28) * 100 = 33.65 % If the solution is benzene and CCl4 dissolved in water or another solvent, the answer depends entirely on how much solvent you have.
As sodium sulfite (Na2SO4) dissolves, it dissociates into its ions: Na2SO4 --> 2Na+ + SO32-