5
The value of 'n' for the valence shells is the number of shells that specific atom has
;need the same number of electrons to fill their valece shells ;have the same number of valence electrons
As: Arsenic 33
To determine the total number of valence electrons in 4.2 g of the N³⁻ ion, first calculate the number of moles of N³⁻ in that mass. The molar mass of nitrogen (N) is approximately 14 g/mol, so N³⁻ has a total of 5 valence electrons (as nitrogen has 5 valence electrons and gains 3 more to form the ion). In 4.2 g of nitrogen, there are about 0.3 moles, which corresponds to approximately 0.3 moles × 3 nitrogen atoms per ion × 5 valence electrons = 4.5 valence electrons in total.
For carbon (C): Atomic number 6, 4 valence electrons. For hydrogen (H): Atomic number 1, 1 valence electron. For nitrogen (N): Atomic number 7, 5 valence electrons. For oxygen (O): Atomic number 8, 6 valence electrons. For phosphorus (P): Atomic number 15, 5 valence electrons.
N and V have same number of valence electrons.The number of valence electrons is 5. V is a metal while N is a non metal.
The value of 'n' for the valence shells is the number of shells that specific atom has
To determine the number of valence electrons from an electron configuration, look at the highest energy level (n value) of the electrons in the configuration. The number of electrons in this highest energy level is the number of valence electrons.
The principal quantum number for valence electrons in lead is 6, because lead has 6 valence electrons in the 6th energy level.
;need the same number of electrons to fill their valece shells ;have the same number of valence electrons
The principal energy level is represented by the main energy level number (n). The valence electrons are the electrons found in the outermost energy level of an atom, which corresponds to the highest principal energy level (n).
As: Arsenic 33
The number of valence electrons in N and O is five and six, respectively. The total number of valence electrons in N2O is 16.
To determine the number of valence electrons in an atom using its electron configuration, look at the highest energy level (n) in the electron configuration. The number of electrons in this energy level is the number of valence electrons.
To determine the total number of valence electrons in 4.2 g of the N³⁻ ion, first calculate the number of moles of N³⁻ in that mass. The molar mass of nitrogen (N) is approximately 14 g/mol, so N³⁻ has a total of 5 valence electrons (as nitrogen has 5 valence electrons and gains 3 more to form the ion). In 4.2 g of nitrogen, there are about 0.3 moles, which corresponds to approximately 0.3 moles × 3 nitrogen atoms per ion × 5 valence electrons = 4.5 valence electrons in total.
For carbon (C): Atomic number 6, 4 valence electrons. For hydrogen (H): Atomic number 1, 1 valence electron. For nitrogen (N): Atomic number 7, 5 valence electrons. For oxygen (O): Atomic number 8, 6 valence electrons. For phosphorus (P): Atomic number 15, 5 valence electrons.
its a valence number which is and above