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Phosphorous acid (H₃PO₃) can undergo ionization in three steps, representing the loss of protons. The equations for the ionization steps are:

  1. ( \text{H}_3\text{PO}_3 \leftrightarrow \text{H}^+ + \text{H}_2\text{PO}_3^- )
  2. ( \text{H}_2\text{PO}_3^- \leftrightarrow \text{H}^+ + \text{HPO}_3^{2-} )
  3. ( \text{HPO}_3^{2-} \leftrightarrow \text{H}^+ + \text{PO}_3^{3-} )

These equations illustrate the sequential release of protons from phosphorous acid.

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