i dont know but still you are not answering me.why?
The van der Waals equation is necessary to describe a gas when it deviates significantly from ideal behavior, particularly under conditions of high pressure and low temperature. Ideal gas laws assume no interactions between gas molecules and that they occupy no volume, which is not the case for real gases. The van der Waals equation accounts for molecular size and intermolecular forces, making it more accurate for real gases, especially those that are polar or have larger molecular sizes.
First, calculate the van der Waals constants (a and b) for Cl2. Then, substitute these values, along with the given values (n = 1.000 mol, V = 22.41 L, and T = 273 K), into the van der Waals equation to find the pressure. Finally, compare the calculated pressure with that predicted by the ideal gas equation (PV = nRT) for the same conditions.
To calculate the change in internal energy (dU) during isothermal expansion using the van der Waals equation of state, you first need to know the initial and final volumes. Use the van der Waals equation to calculate the work done during expansion, which is equal to nRT ln(Vf/Vi). Since it is an isothermal process, the change in internal energy will be equal to the negative of the work done.
The volume correction in the van der Waals equation accounts for the finite size of gas molecules, which are not point particles as assumed in the ideal gas law. This correction introduces the term (b), representing the volume occupied by one mole of gas molecules. The modified volume in the van der Waals equation is expressed as (V - b), where (V) is the total volume available to the gas. This adjustment allows for a more accurate description of real gas behavior under various conditions.
The equation of state for a real gas is typically described by the Van der Waals equation, which accounts for the volume occupied by gas molecules and the attractive forces between them. The equation is: (P + a(n/V)^2)(V - nb) = nRT, where P is pressure, V is volume, n is amount of substance, a and b are Van der Waals constants, R is the ideal gas constant, and T is temperature.
The partial derivative of the van der Waals equation with respect to volume is the derivative of the equation with respect to volume while keeping other variables constant.
Jac van der Waals is known for his work in physics, particularly for his development of the Van der Waals equation of state that describes the behavior of gases and liquids. His research laid the foundation for the study of intermolecular forces.
The Nobel Prize in Physics 1910 was awarded to Johannes Diderik van der Waals for his work on the equation of state for gases and liquids.
The van der Waals constants a and b are used to correct for the attractive forces between gas molecules (a) and the volume occupied by the gas molecules (b) in the van der Waals equation, which provides a more accurate description of gas behavior compared to the ideal gas law.
In short just use algebra to get the equation below Start with [P + a*(n/V)^2] * (V - nb) = nRT which is the standard Van Der Waals equation and solve for n using algebra. which gives the 3rd order equation below. -(ab/V^2)*n^3 + (a/V)*n^2 - (bP+RT)*n + PV = 0 The simplest way to solve this equation is to enter it into Excel and graph it with multible values of n from 0 to whatever gets you to zero. The value that gives you zero is the answer. Be sure you use all the proper units for the other varables. Hope this helps.
Johannes Diderik van der Waals was born on November 23, 1837.
Johannes Diderik van der Waals was born on November 23, 1837.
Hydrogen bonds are the reason for cohesion and Van Der Waals equation is the cause of adhesion.
They are named after Johannes Diderik van der Waals who was the first to postulate about inter molecular forces
First, calculate the van der Waals constants (a and b) for Cl2. Then, substitute these values, along with the given values (n = 1.000 mol, V = 22.41 L, and T = 273 K), into the van der Waals equation to find the pressure. Finally, compare the calculated pressure with that predicted by the ideal gas equation (PV = nRT) for the same conditions.
Johannes Diderik van der Waals died on March 8, 1923 at the age of 85.
Johannes Diderik van der Waals died on March 8, 1923 at the age of 85.