It is the amperage that will kill you. In fact the amperage range is in the milliamps (one thousandths of an amp) that are dangerous.
Less than 1/2 milliamp no sensation
1/2 to 2 milliamps Threshold of perception
2 to 10 milliamps muscular contraction
5 to 25 milliamps painful shock (may not be able to let go)
Over 25 milliamps Could be violent muscular contraction
50 to 100 milliamps Ventricular fibrillation
over 100 paralysis of breathing.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
You can calculate amperage (A) using the formula A = W / V, where W is the power in watts and V is the voltage. Simply divide the power in watts by the voltage to find the amperage.
Not necessarily. Amperage (current) is just one component of electrical power. Power is the product of voltage and current. To calculate power, you need both voltage and amperage.
To calculate the amperage for 2kW, you need to know the voltage of the circuit. For example, if the voltage is 120V, then the amperage would be 16.67A (2000W / 120V = 16.67A). If the voltage is 240V, then the amperage would be 8.33A (2000W / 240V = 8.33A).
To calculate the amperage, you would need to know the voltage of the system. If you assume a standard voltage of 120V, you can calculate the amperage by dividing the wattage by the voltage: 2000 watts / 120 volts = 16.67 amps.
No. Voltage doesn't kill you, amperage does, and the amperage produced by a AA battery is not even enough to cause a tingle. Amperage AND voltage kills. Should also include frequency in that equation. 120 v/ 10 amps of 400 hertz kills faster than 60 hz. Amps with low voltage will do no harm. You need both to kill. One AA battery would not kill you but put together enough of them? Why not?
This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.
it depends on what type of load. Motor amperage will drop off as voltage rises. loads such as lights will increase amperage with voltage rise.
Depends on the voltage and amperage of the battery vs. the voltage and amperage required of the bicycle.
The standard voltage of a wall outlet is 120 volts, and the standard amperage is 15 amps.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
An ammeter measures amperage not voltage.
The standard voltage for a typical electrical outlet is 120 volts, and the standard amperage is 15 amps.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
You can calculate amperage (A) using the formula A = W / V, where W is the power in watts and V is the voltage. Simply divide the power in watts by the voltage to find the amperage.
Not necessarily. Amperage (current) is just one component of electrical power. Power is the product of voltage and current. To calculate power, you need both voltage and amperage.
To calculate the amperage for 2kW, you need to know the voltage of the circuit. For example, if the voltage is 120V, then the amperage would be 16.67A (2000W / 120V = 16.67A). If the voltage is 240V, then the amperage would be 8.33A (2000W / 240V = 8.33A).