The charge of the borate ion (BO3) is -3.
The formula for iron(III) borate is Fe(BO3)3. In this compound, iron is in the +3 oxidation state, and each borate group (BO3) carries a -3 charge. Consequently, three borate groups are needed to balance the charge of one iron ion.
The (oxy) borate ion is (BO3)3-.
A berborite is a colourless trigonal or hexagonal mineral, with the chemical formula Be2(BO3)(OH,F)·(H2O)
The electron pair geometry of the borate ion (BO3^3−) is trigonal planar. This is because the central boron atom is surrounded by three oxygen atoms, with no lone pairs on the boron. The bond angles are approximately 120 degrees, reflecting the arrangement of the electron pairs in a planar configuration.
Neutrons have no charge, protons have a positive charge and electrons have a negative charge.
The oxidation state of Boron in BO3^-3 is +3. This is because the overall charge of the ion is -3, and each oxygen atom has an oxidation state of -2. Hence, the Boron atom must have an oxidation state of +3 to balance the charges.
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borate ion
trigonal planar
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The (oxy) borate ion is (BO3)3-.
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Chemical Composition: Na(Li,Al)3Al6(BO3)3Si6O18(OH)4 - Complex borosilicate
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B + 3O-(-3)=0 B-6+3=0 B=+3 i hope this helps
The formula for copper(II) hypobromite is Cu(BrO).
A berborite is a colourless trigonal or hexagonal mineral, with the chemical formula Be2(BO3)(OH,F)·(H2O)