if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.
The genotype of the plant with colored seed and normal starch in the test cross would be AaBb. This genotype indicates that the plant is heterozygous for both the color gene (A) and the starch gene (B), with the recessive alleles for both traits being a (for color) and b (for starch).
The offspring of a cross between organisms with the genotypes AaBb and AaBb would be referred to as a dihybrid cross, focusing on two different gene pairs (A/a and B/b) segregating independently. The resulting offspring would have a genotype ratio of 9:3:3:1 in a typical Mendelian inheritance pattern.
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Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.
Four different phenotypes can be produced: AABB, AABb, AaBB, and AaBb. This is the result of different combinations of alleles from each parent in the offspring.
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The most accurate description of an organism with genotype AaBb is heterozygous. A homozygous genotype is aaBB and AA.
Ab and ab There would be about a 50/50 ratio of each.
The genotype of the plant with colored seed and normal starch in the test cross would be AaBb. This genotype indicates that the plant is heterozygous for both the color gene (A) and the starch gene (B), with the recessive alleles for both traits being a (for color) and b (for starch).
The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
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They would have a genotype pattern of EE.
The offspring of a cross between organisms with the genotypes AaBb and AaBb would be referred to as a dihybrid cross, focusing on two different gene pairs (A/a and B/b) segregating independently. The resulting offspring would have a genotype ratio of 9:3:3:1 in a typical Mendelian inheritance pattern.
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