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C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and has molar mass of 132 amu.
HNO3
An example of how to get formula mass is shown below with the example of water (H2O). H2O 2 H atoms x 1.01 amu/atom = 2.02 amu 1 O atom x 16.00 amu/atom = 16.00 amu 2.02 amu + 16.00 amu = 18.02 amu
30 amu
30 amu (atomic mass units)
The molecular formula mass of this compound is 240 amu. The subscripts in the actual molecular formula 8,16,8.
The molecular formula mass of this compound is 60.0 amu. The subscripts in the actual molecular formula are 2,4,2.
6,12,6
C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and has molar mass of 132 amu.
The molecular formula mass of this compound is 210 amu. The subscripts in the actual molecular formula Enter the subscripts for C H and O is 7,14.7.
This is impossible. In order to find this you must know the elements in the compound
Mana M Al mansour the answer is 5,10,5
HNO3
8,16,8
Propanol is C3H7OH It's formula mass is 60.09492 amu Rounded to four significant figures it is 60.11 amu
95 amu
84.46 amu