Bromine Pentachloride is the name of BrCI5.
Yes, they form BrCl and BrCl3 . such compounds have covalent bonds and known as Interhalogens.
Ca + Cl2 ----> CaCl Step 1) Ca + Cl2 ----> 2 CaCl There are 2 Cl's on the reaction side so you need 2 on the Product side Step 2) 2Ca + Cl2 ----> 2 CaCl There are now 2 Ca on the product side and you need 2 on the reactant side Voila!
This compound is the chromium phosphate.
They both have the word COMPOUND :)
The formula for bromine monochloride is BrCl. It is a reddish-brown liquid at room temperature and is a chemical compound of bromine and chlorine.
BrCl is a covalent compound because it is formed between two nonmetals (bromine and chlorine) that share electrons to achieve a stable electron configuration.
The compound is Bromine chloride
Bromine Pentachloride is the name of BrCI5.
Yes that is all it contains there for it to be ionic or metallic the bond would have to have a metal for ionic and more than 2 elements for metallic composed of metals
To find the mass of BrCl formed, you first need to determine the limiting reactant by comparing the mole ratios of Cl2 and Br2 in the balanced equation. Once you know the limiting reactant, you can use stoichiometry to calculate the moles of BrCl formed. Finally, convert the moles of BrCl to grams using the molar mass of BrCl.
Bromine monochloride, BrCl
The formula for bromine tetrachloride is BrCl₄.
The formula for monohydrogen monobromide is simply HBr. Remember that the prefix mono means one. This substance is more commonly known as hydrobromic acid.
HCl displays the least ionic character among the given compounds. This is because HCl is a covalent bond between nonmetals, resulting in a sharing of electrons rather than a transfer. NaCl, OCl, and BrCl are all ionic bonds between a metal and a nonmetal, leading to a complete transfer of electrons and a higher degree of ionic character.
While Im not particularly sure that reaction even happens, I guess one could figure it out none the less. If you have 2.74 mol of Cl2 you would expect to get 5.48 mol of BrCl. Because each Cl2 can make 2 BrCl so double the number of moles. Br has a molecular weight of 79.90 and Cl of 35.45 so together that's 115.35 Grams/mol. Since you have 5.48 mol all you have to do is multiply the two numbers together and cancel out the "mol" units to get 631.12 grams of BrCl... again which makes this reaction seem completely unrealistic.... what good is that much BrCl. --------------------------------------------------------------------------------------------------- Well, silly you need to balance it first and provide the equation~ So you probably have: Br2+Cl2=2BrCl correct? So you have 2.74mol Cl2, you need to find ___molBrCl 2.74molCl2 X (2molBrCl/1molCl2) = 5.48molBrCl
Yes, they form BrCl and BrCl3 . such compounds have covalent bonds and known as Interhalogens.