NPK stands for the three most essential nutrients needed for plant growth: Nitrogen (N), Phosphorus (P), and Potassium (K). These nutrients play vital roles in the development of healthy plants and are commonly found in fertilizers to support plant growth.
Nitrogen (N), Phosphorous (P), Potassium (K).
nitrogen (N) phosphorus (P) potassium (K)
ammonia
three primary nutrients which plant need for their growth are : 1.NITROGEN (N) 2.PHOSPHORUS (P) 3.POTTASIUM (K)
Plants need salts containing K, Mg, N, P etc.
It refers to three different nutrients - N is nitrogen, P is potassium, and K is phosphorus. They are often referred to together because they are the major nutrients required by plants.
P. K. N. Burbidge has written: 'Tort'
NPK, where N is Nitrogen, P is phosphorus and K potassium
N, P, K, Fe, Mg, Zn, S, Cu etc.
N. K. P. Salve was born on 1921-03-18.
N. K. P. Salve died on 2012-04-01.
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
You need a formula for this. If the probability (in one toss) of getting head is "p", then the probability of getting exactly k heads out of n tosses is: (n,k) p^k (1-p)^(n-k) where (n,k) denotes the number of combinations of k elements among n. You should also know that (n,k) = n! / (( n-k)! k! ) so here, with n=8, k=6, and p=.5 you have (n,k) = 8*7 / 2 = 28 and your probability is : 28 * 1/2^6 * 1/2^2 = 28 / 256 = 7 / 64
#include<stdio.h> #include<stdlib.h> #include<math.h> #include<conio.h> void main(void) { int K, P, C, J; double A[100][101]; int N; int Row[100]; double X[100]; double SUM, M; int T; do { printf("Please enter number of equations [Not more than %d]\n",100); scanf("%d", &N); } while( N > 100); printf("You say there are %d equations.\n", N); printf("From AX = B enter elements of [A,B] row by row:\n"); for (K = 1; K <= N; K++) { for (J = 1; J <= N+1; J++) { printf(" For row %d enter element %d please :\n", K, J); scanf("%lf", &A[K-1][J-1]); } } for (J = 1; J<= N; J++) Row[J-1] = J - 1; for (P = 1; P <= N - 1; P++) { for (K = P + 1; K <= N; K++) { if ( fabs(A[Row[K-1]][P-1]) > fabs(A[Row[P-1]][P-1]) ) { T = Row[P-1]; Row[P-1] = Row[K-1]; Row[K-1] = T; } } if (A[Row[P-1]][P-1] 0) { printf("The matrix is SINGULAR !\n"); printf("Cannot use algorithm --- exit\n"); exit(1); } X[N-1] = A[Row[N-1]][N] / A[Row[N-1]][N-1]; for (K = N - 1; K >= 1; K--) { SUM = 0; for (C = K + 1; C <= N; C++) { SUM += A[Row[K-1]][C-1] * X[C-1]; } X[K-1] = ( A[Row[K-1]][N] - SUM) / A[Row[K-1]][K-1]; } for( K = 1; K <= N; K++) printf("X[%d] = %lf\n", K, X[K-1]); getch(); }
p-i-n-k
That is the N P K numbers. N=Nitrogen P=Phosphorous K=Potassium. the numbers are always in that order and tell you the percentage.