1 mole of O atoms, or 0.5 moles of o2 molecules.
1
160 grams = 5.64 ounces.
170 grams = 0.374785846 pounds (rounded: 0.375 pounds).
160 grams = 5.64383391 ounces
The percentage of oxygen is 54,84 %.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
1
0.160 kg is equal to 160 grams.
160 grams = 5.6 ounces.
160 grams = 5.64 ounces.
.160 ounces = 4.535 grams.
160 grams = about 5.644 ounces.
the equation of this reaction is C + O2 = CO2 (s) (g) (g) according to this reaction 1mol of Carbon react with same number of moles of Oxygen. and this combination gives 1mol of CO2 as result. so first we have to find the number of moles in the weight we are going to use. 12 grams of carbon contains 1mol so 6 grams of carbon contains ( 1/12 )*6 = 0.5mol 32 grams of Oxygen contains 1mol 16 grams of Oxygen contains ( 1/36 )*16 = 0.5mol as 1mol of C react with 1mol of O2,0.5mol of C react with 0.5mol of O2. this produces equal number of moles (0.5mol) of CO2.
23
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
170 grams = 0.374785846 pounds (rounded: 0.375 pounds).