C2H2N, is not a molecule per se, it is merely the empirical formula for the molecule C8H8N4, which I do not know what it is.
The product of the reaction between nitrogen (N) and oxygen (O2) is nitrogen dioxide (NO2). In this reaction, one nitrogen atom reacts with one molecule of oxygen to form one molecule of nitrogen dioxide. The balanced chemical equation for this reaction is: N + O2 → 2NO2.
Yes, N2 and O2 have unpaired electrons because they have a triple bond between the nitrogen or oxygen atoms, resulting in one unpaired electron in each molecule. Li2 does not have unpaired electrons because it forms a stable bond with shared electrons within the lithium atoms.
Equations for combustion will change with the type of fuel used. For example, the complete combustion of pentane is (C5)(H12) + 3(O2) --> 5(CO2) + 6(H2O). The complete combustion of ethanol is (C2)(H5)(OH) + 3(O2) --> 2(CO2) + 3(H2O).
The balanced equation for the complete combustion of coconut oil (CnH2nO2) in air (O2) is: CnH2nO2 + (3n + 1) O2 → n CO2 + (n + 1) H2O, where n is the number of carbon atoms in the coconut oil molecule.
Positive ion. Examples: H+ Na+ Li+ Be+ N+ Lost multiple electrons? H2+ Na2+ Li3+ H5+
C2 , h5 , oh
my name: hailie, but here r sum more.. hallie heather Hannah Haley Hank Hanzel Hannah Hanna Hugh Harleigh Harley Higinia <H2>Answer</H2> <UL> <LI> <H5>Hunter</H5></LI> <LI> <H5>Hayden</H5></LI> <LI> <H5>Hallie</H5></LI> <LI> <H5>Heather</H5></LI> <LI> <H5>Helga</H5></LI> <LI> <H5>Harold</H5></LI> <LI> <H5>Harry</H5></LI> <LI> <H5>Hope</H5></LI> <LI> <H5>Hester</H5></LI> <LI> <H5>Hannah</H5></LI></UL>
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
You will have to wait until the baby is born, then run a DNA check on the two men. <h5>Sperm usually lives for up to 72 hours; therefore, a woman can conceive any time within those three days. Your post is not a question, although you ended it with a question mark.</h5><h5><br>If you are asking how you can determine who the father is, you have options. </h5><h5>1) DNA test</h5><h5>2) ultrasound to determine how far along you are</h5><h5><br>I would assume that your OB will tell you that a DNA test is the way to be 100% certain.</h5>
Sword Art H5 is my playing web game, launched Instantfuns! Do you know it?
If I knew the difference of an H3 and H5 I would not be asking the question.
The balanced chemical equation for the combustion of ethanol (C2H6O2) is: C2H6O2 (ethanol) + 3 O2 (oxygen) -> 2 CO2 (carbon dioxide) + 3 H2O (water).
Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G
H1 influenza is a hog virus and I'm not sure about H5 (i used my Prier knowledge on this 1)
h5
bhgyuTSFUTYDXHDA BGB H5-
N(o2)3