Fe + O2 --> 2FeO
+2
fe+3=..............* .9 =fe+2
The chemical formula Fe2O3 consists of iron (Fe) and oxygen (O) elements.
Your unbalanced equation is _Al + _Cr2O3 ----> _Cr + _Al2O3. Multiply aluminum (Al) and chromium (Cr) ratio by 2, so each side has the same amount of each element. As a result, the equation 2Al + Cr2O3 -----> 2Cr + Al2O3 is balanced. This is a single replacement reaction.
Formula = Fe(ClO4)2Formula: Fe(ClO4)2
2- iron and oxygen. Should be written as Fe2 O3
2 moles O3 (48 grams/1 mole O3) = 96 grams of ozone ==============
+2
fe+3=..............* .9 =fe+2
Fe3O4 is a complex oxide (a crystaline solid containing more than one cation). In this case Fe exists as both the 2+ and 3+ cation. There are two 3+ ions and one 2+ ion for every four O2- ions. The charge balance is: 2x3+ + 2+ + 4x2- = 0
The oxidation number for O in O3 is -2. In O3, the total charge is 0 because it is a neutral molecule, and the sum of the oxidation numbers of all the atoms in O3 must equal 0. Since there are 3 oxygen atoms in O3, each with an oxidation number of -2, the total charge balances out.
The chemical formula Fe2O3 consists of iron (Fe) and oxygen (O) elements.
Your unbalanced equation is _Al + _Cr2O3 ----> _Cr + _Al2O3. Multiply aluminum (Al) and chromium (Cr) ratio by 2, so each side has the same amount of each element. As a result, the equation 2Al + Cr2O3 -----> 2Cr + Al2O3 is balanced. This is a single replacement reaction.
Formula = Fe(ClO4)2Formula: Fe(ClO4)2
The half-reaction equation representing the reduction of iron (II) ion (Fe^2+) is: Fe^2+ + 2e^- -> Fe
THe oxidation number for 'O3' is zero(0). O3 is ozone, and each oxygen atoms forms two single bonds with each of the other oxygens, forming a triangular arrangement.
When iron (Fe) reacts with chlorine gas (Cl2), they form iron (III) chloride (FeCl3) according to the equation: 2 Fe + 3 Cl2 → 2 FeCl3. This reaction is a redox reaction where iron is oxidized and chlorine is reduced.