Iron(III) sulfide (Fe2S3) breaks down into iron(III) oxide (Fe2O3) and sulfur dioxide (SO2).
To find how many grams of iron can be produced, calculate the molar mass of Fe2S3 and C, then use stoichiometry to determine the amount of Fe that can be produced. 1 mole of Fe2S3 produces 2 moles of Fe, and 1 mole of C produces 3 moles of Fe, so compare the moles of Fe produced from each reactant and choose the limiting reactant. Calculate the amount of Fe produced.
Break Down Barriers was created in 1983.
Lipase can't break down maltose because it is meant to break down lipids. Maltose is a form of a carboydrate, which is broken down by maltase.
Fe2(SO3)2 I don't think the above answer is right...I believe it is Fe2S3
No, you need protease to break down meat.
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
Formula: Fe2S3
Fesub2 S
Ferrous Sulfide = Iron (III) Sulfide Both -> Fe2S3
Fe2S3 is an ionic bond. Iron (Fe) typically forms cations with a +2 charge, while sulfur (S) typically forms anions with a -2 charge. When these two elements combine to form Fe2S3, they do so through an ionic bond where Fe3+ ions are attracted to S2- ions.
Fe2S3 is an ionic compound. It is composed of iron (Fe) cations and sulfide (S) anions, which form an ionic bond through the transfer of electrons.
To calculate the maximum amount of Fe2S3 that can be formed, we need to determine the limiting reactant. Using the balanced equation for the reaction between Fe and S to form Fe2S3, we find that 8 moles of S react with 3 moles of Fe. From 17 g of S, we can calculate the amount of Fe2S3 that can be formed by converting the mass of S to moles and using the mole ratio from the balanced equation.
To find how many grams of iron can be produced, calculate the molar mass of Fe2S3 and C, then use stoichiometry to determine the amount of Fe that can be produced. 1 mole of Fe2S3 produces 2 moles of Fe, and 1 mole of C produces 3 moles of Fe, so compare the moles of Fe produced from each reactant and choose the limiting reactant. Calculate the amount of Fe produced.
The chemical formula for ironite trisulfide is Fe2S3. It consists of two iron (Fe) atoms and three sulfur (S) atoms.
Iron (III) sulfide is not soluble in water.
decomposition