2Fe+3Cl2------>2FeCl3
The elements H, N, O, F, Cl, Br, and I cannot exist alone as stable diatomic molecules because they are highly reactive and typically form bonds with other atoms to achieve a full valence shell. For instance, they often pair with another atom of the same element, resulting in diatomic molecules like H₂, N₂, O₂, F₂, Cl₂, Br₂, and I₂. This tendency to bond helps them attain greater stability through shared electrons. Additionally, their electronegativity and reactivity drive them to seek out bonding partners rather than remaining isolated.
In KCIO2, the overall charge of the compound is zero because potassium (K) has a +1 charge, oxygen (O) has a -2 charge, and the sum of the oxidation states must equal zero. Therefore, the oxidation state of chlorine (Cl) in KCIO2 is +5.
My chemistry teacher always taught us Dr. HOFBrINCl H-Hydrogen O-Oxygen F-Fluorine Br-Bromine I-Iodine N-Nitrogen Cl-Chlorine
The 7 diatomic elements are: hydrogen (H₂), nitrogen (N₂), oxygen (O₂), fluorine (F₂), chlorine (Cl₂), bromine (Br₂), and iodine (I₂). These elements naturally form molecules consisting of two atoms bonded together.
Phosphorous (P) has Nitrogen (N) and Oxygen (O) above it. P=15 N=7 O=8 P=O+N Chlorine (Cl) had Oxygen (O) and Fluorine (F) above it. Cl=17 O=8 F=9 Cl=O+F Bromine (Br) has Chlorine (Cl) and Argon (Ar) above it. Br=35 Cl=17 Ar=18 Br=Cl+Ar
These symbols represent chemical elements: Br - bromine, N - nitrogen, Cl - chlorine, H - hydrogen, O - oxygen, F - fluorine. Each element has its own unique set of properties and is represented by a symbol on the periodic table of elements.
The most electronegative element is Cl (Chlorine), followed by Br (Bromine) and then Se (Selenium). Electronegativity measures an atom's ability to attract electrons towards itself in a chemical bond.
K=39.100 Cl=35.457 O3=48.000 total=122.557 %K = 39.1x100/122.557 %Cl = 35.457x100/122.557 %O = 48.0x100/122.557
2Fe+3Cl2------>2FeCl3
+1 for each K, +6 for S and -2 for each O in K2SO4
Na + Br ₂→ NaBr This happens because: When certain diatomic elements (Br, I, N, Cl, H, O, F) are alone you add a 2 as a subscript so they are (Br₂, I,₂ N₂, Cl₂, H₂, O₂, F₂). But when you cross Na (which has a charge of +1) with Br (which has a charge of -1) They cancel and you get NaBr. Na + Br ₂→ NaBr This happens because: When certain diatomic elements (Br, I, N, Cl, H, O, F) are alone you add a 2 as a subscript so they are (Br₂, I,₂ N₂, Cl₂, H₂, O₂, F₂). But when you cross Na (which has a charge of +1) with Br (which has a charge of -1) They cancel and you get NaBr.
KClO4 is an ionic compound because it is composed of a metal (K) and non-metal (Cl and O) elements. In this case, potassium (K) is a metal that donates an electron to the non-metal elements (Cl and O), resulting in the formation of ionic bonds.
The problem with this question is that bond angles will depend on which molecules are being referred to.PBr2 and PClBr are not compounds they are transient molecules.In VSEPR terms they are odd electron molecules with 7 electrons in the outer shell they will be bent. I do not believe that bond angles are known.P2Cl4 - the molecule is trans Cl2P-PCl2- I don't know if bond angles have been determinedP2Br4 is not well characterised.In PBr3 the Br-P-Br angle is 101 oIn PBr5 the solid is actually PBr4+ Br- PBr4+ is tetrahdral with 109.5o angleMixed halides PClBr2 and PCl2Br are known. I can't find the bond angles for these. VSEPR predicts a trigonal pyramidal shape - bearing in mind that the bond angles in PBr3 and PCl3 are 100 o and 101 o respectively I think a prediction of around 100-101 o would be reasonable for the Cl-P-Br angle.
If yoy think to diatomic (atoms of same element) molecules: O, N, Cl, F, Br, I, H.
-2 for each O, +5 for Br
The oxidation number of Cl in KClO3 is +5. This is determined by assigning -2 to O and +1 to K, and then setting up an equation to find Cl's oxidation number based on the overall charge of KClO3.