bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206
Bismuth-214 produces Polonium-214 by beta- decay. It also produces Thallium-210 by alpha decay, though at a much smaller percentage.
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
Atomic number of radium is 88 and that of bismuth is 83. So atomic number is to be reduced by 5. But as alpha is emitted atomic number reduces by 2. So a beta decay is needed which would increase the atomic number by 1. So 3 alpha decay and one beta decay would make radium into bismuth
When bismuth-213 emits an alpha particle, it transforms into thallium-209. This process is known as alpha decay, where the atomic number decreases by 2 and the mass number decreases by 4 due to the emission of an alpha particle.
Uranium 238 is transformed in thorium 234 by alpha decay.
When bismuth-212 undergoes alpha decay, it becomes thallium-208.
Polonium-218 undergoes alpha decay to form lead-214, which then undergoes beta decay to form bismuth-214.
Bismuth-214 produces Polonium-214 by beta- decay. It also produces Thallium-210 by alpha decay, though at a much smaller percentage.
Three alpha emissions would convert francium-223 to bismuth-215. Francium-223 undergoes three consecutive alpha decay processes, which leads to the transformation into bismuth-215 through radioactive decay.
Lead-214 undergoes beta decay to form Bismuth-214. In beta decay, a neutron is converted into a proton, emitting an electron and an antineutrino.
If Sulfur-34 undergoes alpha decay, it will become silicon-30. This is because in alpha decay, the parent nucleus loses an alpha particle (which is a helium nucleus composed of 2 protons and 2 neutrons), resulting in a new nucleus with an atomic number reduced by 2 and a mass number reduced by 4.
That depends on the type of decay, alpha and beta decay change the atom into a different element but gamma decay does not.
Lead-209 will be left over after the isotope bismuth-213 undergoes alpha decay, as the emission of an alpha particle causes the atomic number of the element to decrease by 2. Bismuth-213 has an atomic number of 83, so after the emission of an alpha particle (which has an atomic number of 2), the resulting element will have an atomic number of 81, which corresponds to lead.
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
Americium-241 undergoes alpha decay to become Neptunium-237. During alpha decay, an alpha particle (two protons and two neutrons) is emitted, resulting in the conversion of Americium-241 to Neptunium-237.
When lead-210 undergoes radioactive decay to become bismuth-210, it undergoes beta decay. In this process, a neutron in the lead-210 nucleus is converted into a proton, emitting a beta particle (an electron) and an antineutrino. This transformation increases the atomic number by one, resulting in the formation of bismuth-210 while the mass number remains the same.
Go nnn and the other one and get it.