Iodine-123 (I-123) decays primarily through beta decay into tellurium-123 (Te-123). This process involves the emission of a beta particle, resulting in a change of the atomic number while maintaining the same mass number. Te-123 is stable and does not undergo further significant radioactive decay.
Iodine-131 is produced through the decay of tellurium-132, which occurs in nuclear reactors as a byproduct of uranium fission. Tellurium-132 undergoes beta decay to transform into iodine-132, which then further decays to iodine-131 through another beta decay process. This transformation is part of the decay chain of certain isotopes produced during the fission of nuclear fuel. Iodine-131 is significant in medical applications, particularly in the treatment of thyroid disorders.
We know that iodine-131 will undergo beta minus decay, and an electron will appear as a result. (An electron antineutrino will also be produced, but we don't want to go there in this topic.)
After decay, Iodine-125 brachytherapy seeds lose their radioactivity and become stable. They no longer emit radiation and pose a reduced risk to surrounding tissues. The decay products may still remain in the body but at very low levels that are generally not harmful.
Iodine-131 is a decaying radioisotope that produces xenon-131 through beta decay. During beta decay, a neutron is transformed into a proton within the nucleus, and a beta particle (an electron) is emitted, resulting in the production of xenon-131.
Iodine-123 (I-123) decays primarily through beta decay into tellurium-123 (Te-123). This process involves the emission of a beta particle, resulting in a change of the atomic number while maintaining the same mass number. Te-123 is stable and does not undergo further significant radioactive decay.
In 1811, Iodine-123 was discovered by Bernard Courtois.
Thyroid tissue.
it has no strong chemical reaction
Iodine-131 decays through beta decay by emitting a beta particle and a gamma ray. This process transforms a neutron in the iodine-131 nucleus into a proton, resulting in the formation of xenon-131.
No, iodine-127 is not radioactive. It is a stable isotope of iodine, which means it does not undergo radioactive decay and does not emit harmful radiation.
Iodine-131 is produced through the decay of tellurium-132, which occurs in nuclear reactors as a byproduct of uranium fission. Tellurium-132 undergoes beta decay to transform into iodine-132, which then further decays to iodine-131 through another beta decay process. This transformation is part of the decay chain of certain isotopes produced during the fission of nuclear fuel. Iodine-131 is significant in medical applications, particularly in the treatment of thyroid disorders.
We know that iodine-131 will undergo beta minus decay, and an electron will appear as a result. (An electron antineutrino will also be produced, but we don't want to go there in this topic.)
Iodine-131 has a half-life of approximately 8 days, which means it takes about that long for half of a given amount of iodine-131 to decay into its stable form, xenon-131. After about 40 days (five half-lives), it will have decayed to a level that is generally considered negligible. The decay process continues, but the rate slows significantly as it approaches stability.
After decay, Iodine-125 brachytherapy seeds lose their radioactivity and become stable. They no longer emit radiation and pose a reduced risk to surrounding tissues. The decay products may still remain in the body but at very low levels that are generally not harmful.
It decays by electron capture to an excited state of tellurium-125.
Here is the equation for the beta minus decay of iodine-131: 53131I => 54131Xe + e- + ve The iodine-131 undergoes a transformation when a down quark within a neutron in its nucleus changes into an up quark. This change is mediated by the weak interaction, or weak force. The neutron then becomes a proton, and an electron is created and ejected from the nucleus along with an antineutrino. To learn more, use the link below to the related question, "What is beta decay?"