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reactants are favored over products in the reaction

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13y ago

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What does it mean if keq1?

I suspect it could be " k eq 1" , or "k =1".


What does it mean if K eq?

reactants are favored over products in the reaction


What is a Right Most digit mean?

What does this mean? The rightmost digit of {eq}n^j{/eq} is the remainder when {eq}n^j{/eq} is divided by {eq}10{/eq}. yep totaly nor random :))


What does cv rating mean on a water valve?

The CV value is the flow rate required to generate 1 psid of pressure loss through the valve. Since pressure drop follows a basic square law the relationship between Cv, flow and pressure loss is as follows: DP = k x Flow^2 eq 1 Where k is a constant that represents the flow shape in the wide open condition. Since Cv is the flow rate at 1 psi of pressure loss then it follows that DP = k x Cv^2 = 1 eq 2 solving for k from eq 2 yields k = 1/Cv^2 eq 3 substituting eq 3 into eq 1 yields DP = (Flow/Cv)^2 Now you have an equation that will tell you the pressure and flow relationship for that particular valve with a particular fully open Cv value. In short, the higher the Cv value the more flow the valve will allow for the same pressure loss or the less pressure loss for the same flow. Good luck


The difference between two numbers is 3 three times the smaller plus two times the larger is 31 what are the numbers?

The difference between two numbers is 3 three times the smaller plus two times the larger is 31 what are the numbers? L = large number S = small number Eq. #1….L...- S =31 Eq. #2...2L + 3S = 31 ….Multiply eq#1 by 3 and add Eq. #1 + Eq. #2 Eq. #1…..3L - 3S =93 Eq. #2…..2L + 3S = 31 EQ.#3…..5L + 0 = 124 …………….....L = 24.8 Substitute L = 24.8 into Eq.#2 Eq. #2..............2L + 3S = 31 Eq. #2...2 * (24.8) + 3S = 31 Eq. #2……....49.6 + 3S = 31 Eq. #2……...............3S = -18.6 Eq. #2…….................S = -6.2 Check in Eq. #1 Eq. #1……….L...- S =31 Eq. #1….24.8..- -6.2 =31 Eq. #1…....24.8 + 6.2 =31 Large# = 24.8 Small# = -6.2


What dose EQ mean in music?

Equalizer


What does the k mean in 1 k?

Thousand.


Solve the simultaneous equations 4x plus 3y equals -5 3x plus 5y equals -12?

4x + 3y = -5 (Eq 1); 3x + 5y = -12 (Eq 2) Eliminate x Eq 1 times 3: 12x + 9y = -15 Eq 2 times 4: 12x +20y = -48 Subtract Eq 1 from Eq 2 11y = -48-(-15) ie 11y = -33 y = -3 Substitute in Eq 1: 4x - 9 = -5, ie 4x = 4 so x = 1 Check in Eq 2: (3 x 1) + (5 x -3) = 3 - 15 = -12. QED


Solve the following system of equation algebraically 3xplus2y equals 4 4xplus 3y equals 7?

3x + 2y = 4 (Eq 1); 4x + 3y = 7 (Eq 2) Eliminate x Eq 1 x 4 = 12x + 8y = 16 (Eq 3) Eq 2 x 3 = 12x + 9y = 21 (Eq 4) Subtract Eq 3 from Eq 4 y = 5 so x = (4 - 10)/3 = -6/3 ie -2 Check Eq 2: (4 x -2) + (3 x 5) = -8 + 15 = 7 QED


What is the solution for X plus 7y equals 39 and 3x-2y equals 2 is?

x + 7y = 39 ....... Eq.13x - 2y = 2 ....... Eq.2multiply Eq.1 with (-3) and so Eq.1 will be :-3x - 21y = -1173x - 2y = 2_________________ by Elimination method ( Eq.1 + Eq.2 ) the result will we :- 21y - 2y = - 115-23y = -115Y = 5to find the value of x, put the value of y in Eq.1 :x + 7y = 39x = 39 - 7yx = 39 - 7(5)X = 4___________________________________________________________you can solve it in another way by using substitution method:x + 7y = 39 ....... Eq.1 ,, you can write it in another form, x = 39 - 7y3x - 2y = 2 ....... Eq.2Put the value of Eq.1 on Eq.23(39 - 7y) - 2y = 2117 - 21y - 2y = 2117 - 23y = 223y = 115 ............ Y = 5to find the value of X , put the value of Y in Eq.1x = 39 - 7yx = 39 - 7(5)x = 39 - 35 .............. X = 4and so in both ways....you got the same answer choose the easiest way for you :)good luck my friend...


X plus 7y equals 39 and 3x minus 2y equals 2?

x + 7y = 39 ....... Eq.13x - 2y = 2 ....... Eq.2multiply Eq.1 with (-3) and so Eq.1 will be :-3x - 21y = -1173x - 2y = 2_________________ by Elimination method ( Eq.1 + Eq.2 ) the result will we :- 21y - 2y = - 115-23y = -115Y = 5to find the value of x, put the value of y in Eq.1 :x + 7y = 39x = 39 - 7yx = 39 - 7(5)X = 4___________________________________________________________you can solve it in another way by using substitution method:x + 7y = 39 ....... Eq.1 ,, you can write it in another form, x = 39 - 7y3x - 2y = 2 ....... Eq.2Put the value of Eq.1 on Eq.23(39 - 7y) - 2y = 2117 - 21y - 2y = 2117 - 23y = 223y = 115 ............ Y = 5to find the value of X , put the value of Y in Eq.1x = 39 - 7yx = 39 - 7(5)x = 39 - 35 .............. X = 4and so in both ways....you got the same answer choose the easiest way for you :)good luck my friend...


What is the formula for Eq for salts using only one chloride?

By adding the molecular weights and dividing by 1 you have the formula for Eq for salts that use only 1 chloride.