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Scandium(III) oxide, represented as Sc₂O₃, indicates that scandium has lost three electrons to form a Sc³⁺ ion, while oxygen typically gains two electrons to form O²⁻ ions. In the compound, two Sc³⁺ ions combine with three O²⁻ ions to achieve electrical neutrality. Thus, scandium in this oxide is in a +3 oxidation state, while oxygen is in a -2 oxidation state.

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