Aluminium.
In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).
The answer is not c.
4Al(s) + 3O2(g) --> 2Al2O3(s) where Al has an oxidation number of 3+
The element with the atomic number 13 is aluminum.
Aluminum (Al) always forms a 3+ cation in its 3rd period of the periodic table.
yes its a reactive element c12 and al do react
Al is oxidized because it loses electrons , O is reduced because it gains electrons.
In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
To find the limiting reactant, first convert the masses of Al and Cl2 to moles. The balanced equation shows that 2 moles of Al reacts with 3 moles of Cl2 to produce 2 moles of AlCl3. Determine the moles produced by each reactant and find the limiting reactant. Finally, calculate the mass of AlCl3 produced using the limiting reactant.
The answer is not c.
The element aluminum has the chemical symbol Al
Yes, this is a redox reaction because there is a transfer of electrons between the reactants (Al losing electrons to become AlCl3, which is reduced, and H+ ions gaining electrons to become H2 gas, which is oxidized).
Al, is not a compound, it is the element aluminum.
Al
4Al(s) + 3O2(g) --> 2Al2O3(s) where Al has an oxidation number of 3+
Mn2O7+Al=