I would imagine, logically, Calcium would react with every element except the Noble Gases - as they already have full outer energy levels, thus being unreactive. You will often find one calcium reacting with one element from group 6, for example Oxygen. CaO (as they strive to reach a full outer shell.)
There is 1 electron in the outer shell of a group one alkali metal. Just the same as there would be two electrons in the outer shell of a group 2 element.
This question is unclear. If you mean 3 full electron shells and nothing else, then it would be argon. But every element after argon has 3 full electron shells also, but they also have other shells with electrons. If you mean a full 3rd energy shell such as in having 3d10 electrons, then it would be Zn but Zn also has 4s2 electrons. So, the question is a vague one.
The noble gases helium and neon are the only elements with completely full outer shells.
The outer shell of nickel is not full. Nickel has an electron configuration of 4s2 3d8, so its outer shell has two electrons which is not the maximum it can hold (which would be 8).
Yes, argon can form ions, but it is less likely to do so because it is a noble gas with a full outer electron shell, making it stable and unreactive. It would require a significant amount of energy to remove an electron from argon to form an ion.
All noble gasses have 8 valence electrons which means outer electrons. As for electrons overall, argon would have 18.
Noble gases have a full outer shell, meaning that they have no valence electrons and have 8 electrons in their outer shell. If the outer shell is full they do not need electrons, so they would not want to bond with another element to form a compound.
It would be a non-metal and a halogen. Group 18 or the noble gases, all have 8 electrons in their outer shell. Therefore, the group before it would have seven electrons in the outer shell. This group is made up of all non-metals.
1 atom of the element, carbon, would have 4 electrons in its outer most shell. It's electron configuration is 1s2 2s2 2px1 2py1. 2 is the outer most shell, so there are 4 electrons in shell 2.
I would imagine, logically, Calcium would react with every element except the Noble Gases - as they already have full outer energy levels, thus being unreactive. You will often find one calcium reacting with one element from group 6, for example Oxygen. CaO (as they strive to reach a full outer shell.)
2 because if it was 8 it would be a full shell. 2 because if it was 8 it would be a full shell. 2 because if it was 8 it would have a full shell....
There is 1 electron in the outer shell of a group one alkali metal. Just the same as there would be two electrons in the outer shell of a group 2 element.
This question is unclear. If you mean 3 full electron shells and nothing else, then it would be argon. But every element after argon has 3 full electron shells also, but they also have other shells with electrons. If you mean a full 3rd energy shell such as in having 3d10 electrons, then it would be Zn but Zn also has 4s2 electrons. So, the question is a vague one.
A chloride ion (Cl-) has an electron configuration of 1s2 2s2 2p6 3s2 3p6, which is the same as that of argon. It has gained one electron to achieve a full outer shell and a stable octet configuration.
Sodium would need to lose one electron in order to obtain a full and stable outer shell, however it would be an ion with a positive charge
Calcium has a full 4s sublevel, but does not have a full "outer shell", per se, because it is not a noble gas.