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The genotype is always the "gene formula", in this case Rr.
The phenotype is the expression of the genes (how the animal or plant looks, functions, or behaves). In this case, it's a bit hard to say what the phenotype would be without knowing what R is!
If the question is about garden peas, and if R is the dominant allele responsible for round seeds, and r the recessive allele producing wrinkled seeds, then the genotype Rr will produce the phenotype of the dominant allele, i.e. round seeds.
What else can I help you with?
How many types of gametes will each parent produce in incomplete phenotypes and genotypes in four o'clock plants?
In four o'clock plants, which exhibit incomplete dominance, the parental genotypes can produce two types of gametes. For example, if one parent has the genotype RR (red) and the other has WW (white), they can each produce gametes containing either R or W alleles. Consequently, the offspring can exhibit a blending of traits, such as pink flowers (RW). Therefore, each parent will produce two types of gametes, leading to a variety of phenotypes in the offspring.
If a homozygous dominant parent and a heterozygous parent are crossed what percentage of the offspring are expected to be homozygous dominant?
Rr
If a Red (RR) and White flower (rr) were crossbred resulting in 100 Rr what phenotype(s) would been seen according to the rules of IN-complete dominance?
In incomplete dominance, the phenotype of the offspring is a blend of the parent traits. If a red flower (RR) is crossed with a white flower (rr), all offspring (Rr) would exhibit a phenotype that is intermediate between red and white, often resulting in pink flowers. Therefore, the observed phenotype in this case would be pink.
What are the phenotypes and genotypes of the offspring from the mating of a red carnation and a pink carnation for incomplete dominance?
The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
Use a punnet square to predict the results of a monohybrid cross starting with the phenotypic and genotypic r?
A punnet square is a 2x2 grid that is used to show the probability of an offspring showing a certain genotype and phenotype. The genotype is shown by using a letter for the trait. A capital letter is used to represent a dominant allele and a lowercase letter is a recessive. Ie: a heterozygous individual would be shown as having genotype Rr for a trait. If their genotype contains at least one dominant allele, then their phenotype is shown as the dominant trait. If the trait is eye color, R being dominant brown eyes, and r being recessive blue eyes, then the individual with either RR or Rr will have brown eyes. and if they have rr, then they have blue eyes. Now back to the punnet square, The top of the square will have the genotype of one parent, and the side will have another parent. If the father is RR, then each column will have a R over it. If they are Rr, then the first column will have an R and the second will have a r. Likewise, if they are recessive, then the top of the square will have rr. The same is shown on the rows on the side. The genotype goes down the two squares on the side. The genotype probability is found by crossing each allele in the boxes. If one box has R over it, and r to the right, then the box contains Rr. This is used to fill in all four boxes. In the end, If you have {RR, Rr, rr, rr} as your resulting genotypes, then there is a 50% chance that the offspring will have Dominant or recessive phenotype. The genotype ratio is then 1:2:1 and the phenotypic ratio is 2:2.
What are the possible gametes types that can be produced from a parent who is YrRr?
Make two punnett squares- one for Yy x YY and one for rr x RR the possible outcomes for Yy x YY are: YY Yy the only outcome for rr x RR is Rr. so the gametes of the two could be either YY Rr or Yy Rr
How many types of gametes will each parent produce in incomplete phenotypes and genotypes in four o'clock plants?
In four o'clock plants, which exhibit incomplete dominance, the parental genotypes can produce two types of gametes. For example, if one parent has the genotype RR (red) and the other has WW (white), they can each produce gametes containing either R or W alleles. Consequently, the offspring can exhibit a blending of traits, such as pink flowers (RW). Therefore, each parent will produce two types of gametes, leading to a variety of phenotypes in the offspring.
How many gametes Gg RR Tt?
Eight different gametes can be produced from an individual with genotype Gg RR Tt. This is because of independent assortment of alleles during meiosis which allows for different combinations of alleles to be present in the gametes.
When crossing a Rr genotype with a rr genotype what will the ratio of RR to rr be in the resulting generation?
The resulting generation will have a 1:1 ratio of RR to rr genotypes when crossing an Rr genotype with a rr genotype, as each parent will contribute one allele to the offspring.
How could a child be considered a hybrid?
a hybrid in animals is when a dominant gene in one parent (pure bred RR) and recessive gene in another parent (pure bred rr) combine.Rrin the punnett square:R Rr Rr Rrr Rr Rr
In tomatoes red fruit color is dominant to yellow and suppose a tomato plant homozygous for red is crossed with one homozygous for yellowso determine the appearance of first filial?
Let the dominant allele, red color, be represented by R,and the recessive alelle, yellow, by r. Both parent plants are homozygous, so their genotypes will be: Red: RR Yellow: rr The cross is therefore: RR X rr Remember that a homozygous genotype can produce only one type of gamete, so the red plant can only produce gametes with R, and the yellow plant can only produce r gametes. Since the F1 generation takes one gamete frrom each parent, and each parent can only produce one type of gamete, then the F1 generation can have only one genotype: F1: Rr That is, all of the offspring from this cross will be heterozygous. Red is dominant over yellow, and all of the offspring carry one R allele, therefore all of the F1 generation will be red in color.
What are the possible genotypes if you do a punnett square with one parent who is Homozygous dominant RR for being resistant to poison ivy and one parent who is allergic to poison ivy rr?
RR X rr 100% Rr Heterozygous resistant for poison ivy.
Percentage of heterozygous individuals obtained from selfing Rr individual is?
In the case of selfing an Rr individual - which is heterozygous - you would expect 50% of the offspring to be heterozygous (Rr), as each parent contributes one allele to the offspring. Each allele has a 50% chance of being passed on.
If a homozygous dominant parent and a heterozygous parent are crossed what percentage of the offspring are expected to be homozygous dominant?
Rr
A pea plant with round seeds has the genotype Rr you cross this plant with a wrinkled seed plant genotype rr what is the probability that the offspring will have wrinkled seeds?
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
What is the ratio of red roan white offspring from the cross of a roan bull with a white cow?
Lets start with using letters to symbolize each allele of each parent: Roan Bull x White Cow --> Rr x rr (where the alleles R = red and r = white). The resulting ratio of offspring is the following: Rr = 50% rr = 50% RR = 0% Since there are too many little "r"'s and not enough big "R"'s, we can only get a cross of white and roan calves to a ratio of 1:1. Red calves do not exist in this cross.
What was the genotype of the offspring that did not share the parent's phenotype?
The genotype of the offspring that had the same phenotype as the parents is rr or wrinkled. The phenotype for the seed shape of both parent plants is round.
