answersLogoWhite

0

If stroke volume increases, more blood is ejected by the heart with each beat. This can lead to increased cardiac output, which is the total amount of blood pumped by the heart per minute. Increased stroke volume can be beneficial as it helps the body meet its oxygen and nutrient demands more efficiently.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Continue Learning about Natural Sciences

What does SV stand for in the relationship CO equals HRSV?

In the relationship CO equals HRSV, SV stands for stroke volume.


In which step of the four-stroke engine cycle does the car realeases CO2 H2O and CO?

exhaust


What is the normal calculate cardiac output in liters if stroke is 75 ml and pulse is 75 bpm?

Cardiac output can be calculated using the formula: Cardiac Output (CO) = Stroke Volume (SV) × Heart Rate (HR). In this case, with a stroke volume of 75 ml and a heart rate of 75 bpm, the calculation would be CO = 75 ml × 75 bpm = 5,625 ml/min, or 5.625 liters per minute. Thus, the normal cardiac output is approximately 5.6 liters per minute.


Explain what would happen to CO2 and nox if the co levels were high?

High CO levels can increase the formation of nitrogen oxides (NOx) through reactions with nitrogen in the atmosphere. This leads to increased NOx levels in the air. However, if CO concentrations are high enough, the combustion process in engines can be inefficient, leading to incomplete combustion and higher CO emissions.


Consider this reaction 3Fe and iquestO and Agrave(s) plus CO(g) d2Fe and AgraveO and Aacute(s) plus CO and iquest(g). Which of the following would increase the rate of the reaction?

To increase the rate of the reaction, you can increase the concentration of the reactants (3Fe and O2), increase the temperature to enhance the kinetic energy of the molecules, or increase the surface area of the solid reactant (Fe) by using smaller particles. Additionally, introducing a catalyst could also speed up the reaction without being consumed in the process.

Related Questions