0
In the reaction involving copper(II) oxide (CuO) and hydrogen gas (H2), hydrogen acts as a reducing agent. The hydrogen reduces CuO to metallic copper (Cu), while itself being oxidized to form water (H2O). This process involves the transfer of electrons, where CuO gains electrons to form Cu, and H2 loses electrons to form H2O. Overall, the chemical reaction can be summarized as: CuO + H2 → Cu + H2O.
What else can I help you with?
What is the oxidizing agent for the reaction CuO H2--Cu H2O?
In the reaction CuO + H₂ → Cu + H₂O, the oxidizing agent is CuO. This is because CuO, which contains copper in the +2 oxidation state, is reduced to elemental copper (Cu) as it gains electrons. Meanwhile, hydrogen (H₂) is oxidized to form water (H₂O), losing electrons in the process.
Is H ion oxidizing in this reaction Cu plus H2O equals CuO plus H2?
In the reaction ( \text{Cu} + \text{H}_2\text{O} \rightarrow \text{CuO} + \text{H}_2 ), the hydrogen ions (H⁺) generated from water are not acting as an oxidizing agent. Instead, copper (Cu) is oxidized to copper(II) oxide (CuO), while water is reduced to hydrogen gas (H₂). In this context, water serves as both a reactant and a source of hydrogen ions, but the oxidation state change indicates copper is primarily undergoing oxidation.
Is Cu oxidized or reduced in CuO plus H2 yields Cu plus H2O?
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
What happens when calcium is mixed with water?
The reaction is:Ca + H2O = Ca(OH)2 + H2
What is the word equation for the reaction between copper oxide and sulfric acid?
CuO + H2SO4 ----> CuSO4 + H2O The products are Copper(II) sulphate and water
What is the limiting reactant when 41.4 grams of cuo are exposed to 2.56 grams of h2 according to the equation cuo h2 yields cu h2o?
cuo
How would you get copper from copper oxide?
you obtain Cu from CuO only by reducing with hydrogen or carbon monooxide: CuO + H2 → Cu + H2O
What is the symbol equation for Copper oxide Hydrogen --------- Copper Water?
CuO + H2 ----> Cu + H2O
What mass of hydrogen is needed to react with 40g of copper oxide CuO plus H2-- Cu plus H20?
To find the mass of hydrogen needed to react with 40g of copper oxide (CuO), first calculate the molar mass of CuO. Then, use stoichiometry to determine the moles of CuO present in 40g. From the balanced chemical equation CuO + H2 -> Cu + H2O, you can determine the mole ratio between CuO and H2. Finally, use the molar mass of hydrogen to calculate the mass of hydrogen needed to react.
What is the oxidizing agent for the reaction CuO H2--Cu H2O?
In the reaction CuO + H₂ → Cu + H₂O, the oxidizing agent is CuO. This is because CuO, which contains copper in the +2 oxidation state, is reduced to elemental copper (Cu) as it gains electrons. Meanwhile, hydrogen (H₂) is oxidized to form water (H₂O), losing electrons in the process.
What happens when hydrogen reacts with copper oxide?
When hydrogen reacts with copper oxide, it reduces the copper oxide to form copper metal and water. This is a redox reaction where hydrogen acts as a reducing agent and copper oxide is oxidized. The balanced chemical equation for this reaction is: 2H2 + CuO -> Cu + H2O.
What is the equation for the reaction copper II oxide reacts with hydrochloric acid?
CuO + H2 ------> Cu + H2O. You shouldn't say "plus" for the reactions, it has to be the arrow as the arrow symbolises lots of complicated reactions, making it different to adding them together.
What is the balanced symbol equation for copper ll oxide reacting with hydrogen?
The balanced symbol equation for copper II oxide reacting with hydrogen is Cu + H2O. This reaction will create copper and water as a result.
What is the reaction for Reduction of copper oxide by hydrogen?
The reaction for the reduction of copper oxide by hydrogen is as follows: CuO(s) + H2(g) -> Cu(s) + H2O(g)
Is H ion oxidizing in this reaction Cu plus H2O equals CuO plus H2?
In the reaction ( \text{Cu} + \text{H}_2\text{O} \rightarrow \text{CuO} + \text{H}_2 ), the hydrogen ions (H⁺) generated from water are not acting as an oxidizing agent. Instead, copper (Cu) is oxidized to copper(II) oxide (CuO), while water is reduced to hydrogen gas (H₂). In this context, water serves as both a reactant and a source of hydrogen ions, but the oxidation state change indicates copper is primarily undergoing oxidation.
Write a word equation for the reaction that takes place in a copper oxide?
Copper oxide (CuO) reacts with hydrogen gas (H2) to form copper (Cu) and water (H2O). The word equation for this reaction is: copper oxide + hydrogen gas → copper + water.
Is Cu oxidized or reduced in CuO plus H2 yields Cu plus H2O?
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
