Depending on the energy of the alpha, fusion into Californium-246 could happen, or elastic Rutherford scattering could happen. If the alpha was energized enough to compensate for the reactions net mass increase (mCf - mCm - mα = 6.86MeV) and the Coulomb barrier (about 26MeV), so about 33MeV total, it could fuse into Cf246. Otherwise it'll bounce off the Cm242 via elastic scattering.
The other product formed when curium-242 is bombarded with an alpha particle is uranium-238.
Nitrogen-14 forms Oxygen-17 when it is bombarded by alpha particles.
An Alpha particle
When a radioactive nucleus emits an alpha particle, it decreases by two protons and two neutrons. This results in a new nucleus with a lower atomic number by 2 and lower mass number by 4. The emitted alpha particle is a helium nucleus (2 protons and 2 neutrons) and carries a positive charge.
It will repel
The other product formed when curium-242 is bombarded with an alpha particle is uranium-238.
Nitrogen-14 forms Oxygen-17 when it is bombarded by alpha particles.
Nitrogen-14 bombarded with an alpha particle (helium-4) gives Oxygen-17.
An Alpha particle
When alpha particles are bombarded on beryllium, the process that occurs is known as the (α, n) reaction. In this reaction, the alpha particle collides with a beryllium nucleus, causing it to absorb the alpha particle and become an unstable nucleus. This unstable nucleus then decays, emitting a neutron. The probability of this reaction occurring is relatively low, which is why not all alpha particles result in neutron production.
This particle will be rejected.
This particle is rejected.
In the reaction where nitrogen-14 absorbs an alpha particle, we see the formation of oxygen-17 and a proton. Here's how it looks: 714N + 24He => 11P + 817O Note that the alpha particle is written the way it is because we know that an alpha particle is a helium-4 nucleus. Simple and easy. The equation is balanced, and you can observe that by adding the subscript and the superscript numerals on one side and checking them against those on the other side. In this case, 7 + 2 = 1 + 8, and 14 + 4 = 1 + 17.
When a radioactive nucleus emits an alpha particle, it decreases by two protons and two neutrons. This results in a new nucleus with a lower atomic number by 2 and lower mass number by 4. The emitted alpha particle is a helium nucleus (2 protons and 2 neutrons) and carries a positive charge.
When an alpha particle is released by an atom, the atom loses two protons and two neutrons, resulting in a different element being formed. This process is known as alpha decay.
There are 2 neutron in an alpha particle.
Alpha Particle