Water is considered incompressible, so you can't change its volume.
Only way to get a lesser volume of water is to use less of it. And if you use less, but in a smaller volume, the density stays the same.
Only times water changes density is when you change its state, into steam or ice, or if you add other chemicals to it. But then it's not pure water in a liqued state any more.
Density stays constant no matter what the volume is. Density is measured in units of mass per unit of volume. If the volume increases, so does the mass and the density stays the same.
example: The density of a liquid is 2grams/liter
So if there is one liter, obviously, there are 2 grams of the substance. Now lets change the volume to 5 liters. Now there are 10 grams of the substance. The new density is:
10 grams/ 5 liters which reduces to 2grams/liter. So the density doesn't change regardless of the volume.
Note: this assumes that pressure stays constant at both volumes, which may not be true for very large volumes.
To calculate the water difference when the density changes, you would need to account for the change in volume due to the density change. Use the formula: Difference in water volume = Original water volume / Original water density - Original water volume / New water density. Multiply this difference in volume by the new water density to obtain the actual water difference.
No, as long as it is the same peice of ice. The volume and the density change but not the mass
Density = mass / volume. So if the volume changes, the density will obviously also change.
No, the density of a bathtub full of water would not be the same as just 1 gram of water. The density of water is a constant value regardless of the amount of water present. Density is defined as mass per unit volume, so 1 gram of water would have the same density as any volume of water.
The density of water changes at different temperatures. As temperature goes up, density goes down.
Density = mass / volume. So if the volume changes, the density will obviously also change.
To calculate the water difference when the density changes, you would need to account for the change in volume due to the density change. Use the formula: Difference in water volume = Original water volume / Original water density - Original water volume / New water density. Multiply this difference in volume by the new water density to obtain the actual water difference.
No, as long as it is the same peice of ice. The volume and the density change but not the mass
No, your density does not change when you are in water. Your density is determined by your mass and volume, and it remains constant regardless of the medium you are in.
Density = mass / volume. So if the volume changes, the density will obviously also change.
mass and volume
yes. the density of a element will not change only the mass and volume will.
The density of water does not change when the volume changes. This is because density is a proportion of weight to volume. The density of water changes with temperature, but is approximately 1g/ml.
Mass and volume.
The only way to change the mass of water would be to either add more of it (which wouldn't change it's density - density is an intensive property, not extensive) or to change the isotopes of hydrogen and oxygen in the water - thus getting "heavy water" such as is present as an intermediate materiel in the refining of tritium and as a moderator in some nuclear reactors.
No, the density of a bathtub full of water would not be the same as just 1 gram of water. The density of water is a constant value regardless of the amount of water present. Density is defined as mass per unit volume, so 1 gram of water would have the same density as any volume of water.
A rock's density remains the same when submerged under water because its mass and volume do not change in the water. Density is calculated by dividing an object's mass by its volume, and since both the mass and volume of the rock remain constant underwater, its density also stays the same.