It depends on the reaction. It may be "nothing", or it may serve to drive the reaction in one or the other direction.
The volume is doubled.
Eqilibrium is not affected by any of the factors such as pressure,volume,catalyst,forward or backward reactions
The density of the solid substance remains unchanged when it is cut in half. The mass and volume are both halved, which means the ratio of mass to volume, i.e., density, stays the same.
When a metal ball is heated, its volume increases due to thermal expansion. As the temperature rises, the metal's atoms vibrate more vigorously and tend to occupy more space, causing the ball to expand. This increase in volume occurs uniformly, affecting the entire structure of the ball. However, the mass of the metal remains unchanged during this process.
According to Charles's Law, the volume of a gas is directly proportional to its temperature when pressure is held constant. If the temperature of a gas doubles, its volume will also double, assuming that the amount of gas and the pressure remain unchanged. This relationship highlights the behavior of gas molecules, which move more vigorously at higher temperatures, causing the gas to expand.
The volume remain unchanged.
V=RT/p so it depends on how much the decrease is: if both are halved then volume is unchanged!
It depends on whether the height remains unchanged or increases in the same proportion as the radius.
Since the volume of a cone is proportional to the square of the radius (look at the formula), double the radius would mean four times the volume.
The volume is doubled.
Eqilibrium is not affected by any of the factors such as pressure,volume,catalyst,forward or backward reactions
The density of the solid substance remains unchanged when it is cut in half. The mass and volume are both halved, which means the ratio of mass to volume, i.e., density, stays the same.
If you increase both the volume and mass of an object proportionally, the density will remain the same. However, if you increase the mass while keeping the volume constant, the density will increase. Likewise, if you increase the volume while keeping the mass constant, the density will decrease.
If all other dimensions are left unchanged, doubling the height doubles the volume.
Yes because the amount of liquid is still the same, nothing is added or taken away If the temperature and pressure are unchanged then the volume of the liquid is unchanged regardless of the container it is in.
The mass and weight are unchanged. The volume is reduced.
I'd need to review what happened in number-1 before I could answer that. I do know that if only the length of a rectanguar prism is tripled, while the other two dimensions remain unchanged, then its volume triples.