The atomic number of Selenium is 34.
According to 'Little and Jones' scale Cl 2.83 Se 2.48 S 2.44
The correct arrangement of selenium (Se), chlorine (Cl), and sulfur (S) in order of increasing ionization energy is S < Se < Cl. Ionization energy tends to increase across a period and decrease down a group in the periodic table. Since Cl is in the same period as S and Se but further to the right, it has the highest ionization energy. Sulfur, being below and to the left of chlorine and selenium, has the lowest ionization energy of the three.
Neon is a much smaller atom than selenium because neon has fewer occupied energy levels so it has a considerably smaller atomic radius. For that reason, it will be more difficult to remove an electron from Ne than Se, so Ne has the greater ionization energy.
Selenium (Se) has an atomic weight of 79,04.
Bromine (Br) is more reactive than chlorine (Cl) and selenium (Se). Bromine has a lower ionization energy and a larger atomic radius compared to chlorine and selenium, making it more willing to participate in chemical reactions.
The element with the smallest atomic radius among Ge, Se, Br, and As is Arsenic (As). Atomic size generally decreases across a period from left to right, so the elements in this group progress in order of increasing atomic radius: Germanium (Ge) > Selenium (Se) > Bromine (Br) > Arsenic (As).
The atomic radii of elements follow a general trend: As you move down a group on the periodic table, atomic radius generally increases. Among the three elements mentioned, Se would have the largest atomic radius, followed by Te, with Br having the smallest atomic radius.
Se < O < K < Cs - Atomic radius decreases across a period from left to right on the periodic table, while it increases down a group. Therefore, Se has the smallest atomic radius, followed by O, then K, and Cs has the largest atomic radius.
Se should have a larger ionization energy than Br. This is because Se, located in the higher period on the periodic table, has a larger atomic radius compared to Br. As you move across a period from left to right, the ionization energy generally increases due to increased effective nuclear charge.
No. The Se ion will be larger than the Br ion. The more negative the anion's charge, the larger the radius (more electrons = stronger repulsion between the electrons; so, more distance between them). Se would become "Se2-" as an anion, and Br would become "Br1-". Because Se's "2-" anion charge is more negative than Br's "1-" anion charge, and because Se would have more relative electrons to protons than Br, there is more repulsion between electrons, and distance, within the Se ion. So, the Se ion has a larger radius. Hope it helps.
Y (biggest) Fe Ga S F (smallest)
An element that has a larger ionic radius than calcium is strontium. Strontium is located below calcium in the same group of the periodic table, which means it has an extra energy level and therefore a larger ionic radius.
The atomic number of Selenium is 34.
According to 'Little and Jones' scale Cl 2.83 Se 2.48 S 2.44
.. .. .. :Cl - Se - Cl: .. .. .. There are two dots above the Cl, Se, and other Cl. There are also two dots below the Cl, Se, and other Cl. There are two dots to the left of Cl, and two dots to the right of the other Cl. The dash (-) represents two dots. So, there are a total of 20 electrons. Se has 6, and each chlorine has 7. 6 + 7(2) = 20
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