Steam will have the greatest entropy
Not enough information to answer. Water does not do work when transformed into steam. Once it exists as steam, work can be done as it converts back to water. You will always get less out than you put in. The energy you put in is called the enthalpy of vaporization, (delta H), is also called heat of vaporization or heat of evaporation. The energy required to transform water from a liquid into a gas at atmospheric pressure is 40.68 kilojoules per mole 2260 kilojoules per kilogram. Energy is the ability to do work. Creating steam requires energy. Water does not do work when transformed into steam. Steam, after it is created, can do work and in the normal steam engine, it is then converted back to water. That process involves a few basic issues such as pressure, temperature change and entropy which are not available with the data provided.
1 mole of iron atoms has the greatest mass - 55,845 g.
In free expansion, the gas expands without doing work and without heat exchange with the surroundings. For one mole of an ideal gas expanding isothermally and reversibly from volume ( V ) to ( 2V ), the entropy change (( \Delta S )) can be calculated using the formula ( \Delta S = nR \ln\left(\frac{V_f}{V_i}\right) ). Here, ( n = 1 ) mole, ( R ) is the gas constant, and ( \frac{V_f}{V_i} = 2 ). Thus, the entropy change is ( \Delta S = R \ln(2) ).
They will form one mole of water.
A mole of water weighs more than a mole of sucrose. This is because the molar mass of water (18 g/mol) is less than the molar mass of sucrose (342 g/mol).
One mole of water at 273 K would have greater entropy because liquid water has higher entropy than solid ice due to increased molecular motion and disorder in the liquid state. The molecules in water have more degrees of freedom to move and interact compared to the more ordered structure of ice.
Not enough information to answer. Water does not do work when transformed into steam. Once it exists as steam, work can be done as it converts back to water. You will always get less out than you put in. The energy you put in is called the enthalpy of vaporization, (delta H), is also called heat of vaporization or heat of evaporation. The energy required to transform water from a liquid into a gas at atmospheric pressure is 40.68 kilojoules per mole 2260 kilojoules per kilogram. Energy is the ability to do work. Creating steam requires energy. Water does not do work when transformed into steam. Steam, after it is created, can do work and in the normal steam engine, it is then converted back to water. That process involves a few basic issues such as pressure, temperature change and entropy which are not available with the data provided.
The SI unit of entropy is joules per kelvin (J/K). Entropy is a measure of the disorder or randomness in a system, and it quantifies the amount of energy that is not available to do work.
To find the number of molecules in 0.9 grams of steam (water vapor), we first need to determine the number of moles. The molar mass of water is approximately 18 grams per mole. Therefore, 0.9 grams of steam is about 0.05 moles (0.9 g / 18 g/mol). Using Avogadro's number (approximately (6.022 \times 10^{23}) molecules per mole), we find that 0.9 grams of steam contains about (3.01 \times 10^{22}) molecules.
No. A mole of hydrogen (in its normal form) weighs 2 grams. A mole of water weighs 18 grams.
1 mole of iron atoms has the greatest mass - 55,845 g.
In free expansion, the gas expands without doing work and without heat exchange with the surroundings. For one mole of an ideal gas expanding isothermally and reversibly from volume ( V ) to ( 2V ), the entropy change (( \Delta S )) can be calculated using the formula ( \Delta S = nR \ln\left(\frac{V_f}{V_i}\right) ). Here, ( n = 1 ) mole, ( R ) is the gas constant, and ( \frac{V_f}{V_i} = 2 ). Thus, the entropy change is ( \Delta S = R \ln(2) ).
w=-p.v =-(1.0*100)=-100KJ
6.022 * 10^23 = 1 mole 3.011 * 10^23 = 1/2 a mole
The mole ratio of salt (Na2SO4) to water in Na2SO4.10H2O is 1:10. This means that for every 1 mole of Na2SO4, there are 10 moles of water molecules.
Its all to do with enthlapy and entropy. Anything which is soluble usually has a negative standard enthlapy of solution - the energy involved when 1 mole of solute dissolves in a solvent to give an infinately dilute solution. However, NaCl has a slightly positive enthalpy of solution, yet it dissolves. The reason for this is entropy - the change in the amount of disorder. When NaCl dissolves in solution, there is more chaos, more molecules within the solution. Any process that has a large positive entropy change will be favourable - spontaneous and can occur (reaction will 'go'). However, with CaO, the Ca2+ formed in solution has a high affinity (attraction to) for water molecules, hence a lot of water molecules are arranged orderly - less chaos and hence a negative entropy. This should in effect make the compound insoluble, however, the slight solubility is due to it still having a negative enthalpy change of solution - hence despite entropy it is still slightly soluble. (You may be asking how is dissolving CaO possible if entropy is negative? The entropy of the system maybe negative, but the entropy of the surroundings is positive (dissolving gives out heat - exothermic), hence the overall entropy (sum of both entropies) is positive and the reaction will 'go'.
mole