To find the number of formula units in 40.0 g of magnesium chloride (MgCl2), first calculate its molar mass. The molar mass of MgCl2 is approximately 95.21 g/mol (24.31 g/mol for Mg and 35.45 g/mol for Cl, multiplied by 2). Next, divide the mass of the sample by the molar mass: 40.0 g ÷ 95.21 g/mol ≈ 0.420 mol. Finally, multiply the number of moles by Avogadro's number (6.022 x 10²³ formula units/mol) to get approximately 2.53 x 10²³ formula units of MgCl2.
To find the number of formula units in 10.6 g of magnesium chloride (MgCl₂), first calculate its molar mass. The molar mass of MgCl₂ is approximately 95.21 g/mol. Then, convert grams to moles: (10.6 , \text{g} \div 95.21 , \text{g/mol} \approx 0.111 , \text{mol}). Finally, multiply the moles by Avogadro's number ((6.022 \times 10^{23}) units/mol) to get the number of formula units: (0.111 , \text{mol} \times 6.022 \times 10^{23} \approx 6.69 \times 10^{22}) formula units of magnesium chloride.
To find the number of formula units in 11.8 g of magnesium chloride (MgCl₂), first calculate the molar mass of MgCl₂, which is approximately 95.3 g/mol. Then, divide the mass of the sample by the molar mass: ( \frac{11.8 , \text{g}}{95.3 , \text{g/mol}} \approx 0.124 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number ((6.022 \times 10^{23} \text{ units/mol})): ( 0.124 , \text{mol} \times 6.022 \times 10^{23} \approx 7.47 \times 10^{22} ) formula units.
9 g calcium is equal to 0,224 moles.
The atomic mass of zinc is approximately 65.38 atomic mass units.
G/mol
g/mol
0,806 mol of the element potassium (K) is equal to 31,51 g.
To find the number of formula units in 40.0 g of magnesium chloride (MgCl2), first calculate its molar mass. The molar mass of MgCl2 is approximately 95.21 g/mol (24.31 g/mol for Mg and 35.45 g/mol for Cl, multiplied by 2). Next, divide the mass of the sample by the molar mass: 40.0 g ÷ 95.21 g/mol ≈ 0.420 mol. Finally, multiply the number of moles by Avogadro's number (6.022 x 10²³ formula units/mol) to get approximately 2.53 x 10²³ formula units of MgCl2.
The molar mass of a substance is the mass of one mole of that substance, expressed in units of grams per mole (g/mol).
To convert molar mass from grams per mole (g/mol) to atomic mass units (amu) using a g/mol to amu calculator, simply input the molar mass in g/mol into the calculator. The calculator will then provide you with the equivalent molar mass in atomic mass units (amu). This is the most efficient way to make this conversion accurately and quickly.
To find the number of formula units in 10.6 g of magnesium chloride (MgCl₂), first calculate its molar mass. The molar mass of MgCl₂ is approximately 95.21 g/mol. Then, convert grams to moles: (10.6 , \text{g} \div 95.21 , \text{g/mol} \approx 0.111 , \text{mol}). Finally, multiply the moles by Avogadro's number ((6.022 \times 10^{23}) units/mol) to get the number of formula units: (0.111 , \text{mol} \times 6.022 \times 10^{23} \approx 6.69 \times 10^{22}) formula units of magnesium chloride.
molar mass of MgCl2=95.211g/mol mol=mass/molar mass=34.8g*mol/95.211g=0.3655039859molMgCl2 #of anything=mol*Avogadro's#=0.3655mol*6.022*1023formula units/mol answer= 2.20*1023
To find the number of CaH2 formula units in 7.596 g of CaH2, we first calculate the molar mass of CaH2, which is 42.08 g/mol. Then, we use this molar mass to convert the mass to moles (7.596 g / 42.08 g/mol = 0.1804 mol). Finally, we use Avogadro's number to convert moles to formula units (0.1804 mol * 6.022 x 10^23 formula units/mol = 1.09 x 10^23 formula units).
To convert atomic mass units (amu) to grams per mole (g/mol), you need to multiply the amu value by the molar mass constant, which is approximately 1 g/mol. This will give you the mass of one mole of the substance in grams.
To find the number of formula units in 11.8 g of magnesium chloride (MgCl₂), first calculate the molar mass of MgCl₂, which is approximately 95.3 g/mol. Then, divide the mass of the sample by the molar mass: ( \frac{11.8 , \text{g}}{95.3 , \text{g/mol}} \approx 0.124 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number ((6.022 \times 10^{23} \text{ units/mol})): ( 0.124 , \text{mol} \times 6.022 \times 10^{23} \approx 7.47 \times 10^{22} ) formula units.
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.