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1 mole has 6,022 140 857.10e23 atoms.
Fractions of atoms (as 5,25) doen't exist.

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Calculate the number of moles in 0.525 g of AgCl.?

moles= mass/Mr so 525 divided by the Mr of ZnCl-2 Mr of ZnCl-2= (Ar of Zn= 65.37)+(2 x Ar of Cl= 2 x 35.5= 71) = 136.37 moles= 525/136.37 = 3.85 moles to 3 significant figures. (in grams) divide the answer by 1000 to get mg so 3.85/1000= 0.00385 moles


What volume of 2.40 M SrCl2 is needed to prepare 525 ml of 5.00 mM SrCl2?

First, calculate the moles of SrCl2 needed for the 525 ml solution: (0.525 L) x (5.00 mM) = 0.00263 moles. Then, use the molarity formula to find the volume of the 2.40 M SrCl2 solution needed: (0.00263 moles) / (2.40 mol/L) = 0.001096 L = 1.10 ml.


How many miles is 525 meters?

Divide by 1609.34


If given that natural sample of iron has isotopes 54Fe2656Fe26 and57Fe26 are available as of 510 and 15 total atoms in the universe respectively.What will be the average atomic mass of iron(Fe)?

To calculate the average atomic mass of iron (Fe), we need to consider the isotopic abundances and their respective masses. Given that there are 510 atoms of (^{54}\text{Fe}), 0 atoms of (^{56}\text{Fe}), and 15 atoms of (^{57}\text{Fe}), the total number of atoms is (510 + 0 + 15 = 525). The average atomic mass can be calculated using the formula: [ \text{Average atomic mass} = \frac{(54 \times 510) + (56 \times 0) + (57 \times 15)}{525} = \frac{27540 + 0 + 855}{525} \approx 52.5 , \text{u} ] Thus, the average atomic mass of iron is approximately 52.5 u.


What one is greater 525 mL or 525 cL?

A millilitre is one one thousandth of a litre. A centilitre is one one hundredth of a litre. 525 millilitres is 0.525 litres. 525 centilitres is 5.25 litres. 525 centilitres is larger. Centilitres are not used, millilitres are always preferred. The only time cl are used are on a very few wine bottle labels.

Related Questions

How many hydrogen molecules are needed to produce 525 grams of ammonia?

To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.


Calculate the number of moles in 0.525 g of AgCl.?

moles= mass/Mr so 525 divided by the Mr of ZnCl-2 Mr of ZnCl-2= (Ar of Zn= 65.37)+(2 x Ar of Cl= 2 x 35.5= 71) = 136.37 moles= 525/136.37 = 3.85 moles to 3 significant figures. (in grams) divide the answer by 1000 to get mg so 3.85/1000= 0.00385 moles


What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution?

To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.


How many seconds pass in 525 hours?

How many Seconds Pass in 525 Hours?


What volume of 2.40 M SrCl2 is needed to prepare 525 ml of 5.00 mM SrCl2?

First, calculate the moles of SrCl2 needed for the 525 ml solution: (0.525 L) x (5.00 mM) = 0.00263 moles. Then, use the molarity formula to find the volume of the 2.40 M SrCl2 solution needed: (0.00263 moles) / (2.40 mol/L) = 0.001096 L = 1.10 ml.


How many times does 35 go into 525?

fifteen 525 / 35 = 15


525 meters is how many kilometers?

There are 1000 metres in one kilometre. Therefore, 525 metres is equal to 525/1000 = 0.525 kilometres.


How many times can 5 go into 525?

To determine how many times 5 can go into 525, you would perform division. The formula is: 525 ÷ 5 = 105. Therefore, 5 can go into 525 105 times.


How many days are 525 hours?

525 hours is 21.88 days.


How many yards in 525 meters?

525 meters = 574.15 yards.


How many miles is 525 km?

525 km = 326 miles.


How many feet is in 525 meters?

525 Meters = 1,722.44 feet