To balance the equation involving calcium hydroxide (Ca(OH)₂), phosphoric acid (H₃PO₄), calcium phosphate (Ca₃(PO₄)₂), and water (H₂O), we need to ensure that the number of each type of atom is the same on both sides. The balanced equation is:
3 Ca(OH)₂ + 2 H₃PO₄ → Ca₃(PO₄)₂ + 6 H₂O.
This indicates that three moles of calcium hydroxide react with two moles of phosphoric acid to produce one mole of calcium phosphate and six moles of water.
One possible reaction is 2 NaOH + H3PO4 = Na2HPO4 + 2 H2O.
The balanced equation for the reaction between SO3 and H2O is: SO3 + H2O → H2SO4
Phosphorus
This is not an equation at all. An example of a correct (and balanced) equation would be: 2H2 + O2 --> 2 H2O
The balanced equation for BaCO3 + 2HI is BaCO3 + 2HI → BaI2 + H2O + CO2.
One possible reaction is 2 NaOH + H3PO4 = Na2HPO4 + 2 H2O.
The balanced chemical reaction between phosphoric acid (H3PO4) and sodium hydrogen carbonate (NaHCO3) is: H3PO4 + NaHCO3 -> NaH2PO4 + CO2 + H2O This reaction produces sodium dihydrogen phosphate, carbon dioxide, and water.
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
In H2O the conjugate base is H2PO4-, being conjugated to the acid H3PO4. As well: H3PO4 is conjugated acid to the base H2PO4-.
There is no reaction. Two acids cannot react with each other.
This equation is P4O10 + 6 H2O -> 4 H3PO4.
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
CaCl2 and H2O
The balanced chemical equation for the reaction between cesium hydroxide solution (CsOH) and phosphoric acid (H3PO4) is: 3 CsOH + H3PO4 → Cs3PO4 + 3 H2O This equation is balanced because there is an equal number of atoms of each element on both sides of the equation.
Na3PO4+H2O->NaOH+H3PO4 just balance it.
The coefficient in front of water in the balanced chemical equation for the reaction between H3PO4 and KOH to form K3PO4 and water is 4. This means that four molecules of water are formed in this reaction for every one molecule of H3PO4 and three molecules of KOH that react.