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When cuso45h2o is heated in a crucible there is a loss of water how is the amount of water loss determined?
The amount of water loss from cuso4·5h2o can be determined by measuring the weight of the crucible and compound before and after heating. The initial weight represents the compound with water, and the final weight after heating will show the loss of water as the difference in weight. By subtracting the initial weight from the final weight, the amount of water lost can be calculated.
What is the mass of water in grams that can be removed with heat from 3.30 moles of CuSO45H2O?
To find the mass of water that can be removed from 3.30 moles of CuSO₄·5H₂O, we first note that each formula unit of CuSO₄·5H₂O contains 5 moles of water. Therefore, 3.30 moles of CuSO₄·5H₂O contains (3.30 \times 5 = 16.5) moles of water. Since the molar mass of water (H₂O) is approximately 18 grams per mole, the mass of water that can be removed is (16.5 \times 18 \approx 297) grams.
