Imagine a decimal number, for example, 123 (hundred and twenty-three). Each digit has a corresponding place-value; the right-most digit has the place-value 1, the next digit (counting from the right) has the place-value 10, the next digit hast eh place-value 100. The right-most position (where the digit "3" is in this example) is in the position of least value - the least significant position.
When several bits represent an integer, the situation is the same, except that the numbers are in base-2 instead of base-10 (each position is worth twice as much as the position to the right). But you still have the concept of place-value, and the digit that represents the 1's position is the "least significant bit".
significant figures in the original numbers used in the calculation. This means the final answer should be rounded to the same number of significant figures as the number with the least amount of significant figures.
the measured quantity with the least number of significant figures. For example, if you multiply a quantity with 3 significant figures by a quantity with 2 significant figures, your result should have 2 significant figures.
yes at least a little bit
When the contents of a register are shifted left, each bit moves to the next higher bit position, and a zero is typically inserted on the rightmost side. This operation effectively multiplies the value by two for each left shift. Conversely, when shifted right, each bit moves to the next lower bit position, with a zero or the sign bit (in the case of signed numbers) inserted on the left. This right shift operation effectively divides the value by two for each shift, discarding the least significant bit.
The least count of a measuring instrument is the smallest value that can be measured with the instrument. It determines the precision of the measurement. Significant figures, on the other hand, are the digits in a number that carry meaning about the precision of the measurement. The number of significant figures in a measurement is related to the least count of the instrument used to make that measurement.
Least Significant Bit. Least Significant Byte. (Depends on use.)
1
Least significant bit.
I assume you mean a binary representation of a number.The "least significant bit" (usually the one to the far right but in some languages it has another placement) is "ones"the next most significant bit are the twosThe third most significant bit are the foursetc.So if your number is 37there is one 32 (the sixth most significant bit)no 16's (the fifth most significant bit)no 8's (the fourth most significant bit)one 4 (the third most significant bit)no 2's (the second most significant bit)one 1 (the least most significant bit)if we are to fill an 8 bit "word " we get:0010 0101
It is not. It is probably the least significant question that I have answered! It is not. It is probably the least significant question that I have answered! It is not. It is probably the least significant question that I have answered! It is not. It is probably the least significant question that I have answered!
32 bit
The Bit/Byte order (endianess) of a computer is dependent on the central processing unit (CPU). The large portion of personal computers today are based on the x86 architecture and use a little-endian byte order and least significant bit (LSB) bit order.
The bits in a numeric value like 00000000 00110011 have a decimal value based on the bit position. The most significant bit is the one that has highest decimal value and is the left most bit. The right most bit is the least significant bit. High-order bits are the half of the number of bits that have the highest values, the left most bits in the 16 bit value above The low order bits in this case are the right most bits. This should not be confused with bit placement in memory/cpu registers. Intel/AMD cpus are little edian, meaning that the most significant part is physically right and the lest significant is left most (the bits are not in reverse order). Google for a more detailed info.
bool is_even(long int num) { return !(num & 1); //when the number is even(divisible by two), //its least significant bit is 0 }
0111-1111
The Auxiliary Carry flag of the Intel 8085 is used to store the carry/borrow from the least significant 4 bits of an 8 bit arithmetic operation. This bit (and the Carry flag from the most significant 4 bits) is needed by the Decimal Adjust Accumulator instruction to convert the result of the 8 bit arithmetic operation to correct 2 digit Binary Coded Decimal format.
All factors are equally significant.