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To determine the molecular formula from the empirical formula (C₃H₄O₃) and the given molar mass (264 g), first, calculate the molar mass of the empirical formula: C (12.01 g/mol) × 3 + H (1.01 g/mol) × 4 + O (16.00 g/mol) × 3 = 88.11 g/mol. Next, divide the given molar mass by the empirical formula mass: 264 g / 88.11 g/mol ≈ 3. This means the molecular formula is three times the empirical formula, resulting in C₉H₁₂O₉.
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